Answer:
0.8684 atm
Explanation:
Using combined gas equation,
PV / T = k
P1*V1 / T1 = P2*V2 / T2
P1 = 1.10 atm
P2 = ?
V1 = 2.5L
V2 = 3.9L
T1 = 298k
T2 = 367k
P1*V1 / T1 = P2*V2 / T2
Making P2 the subject of formula;
P2 = P1*V1*T2 / V2*T1
P2 = 1.1*2.5*367 / 3.9*298
P2 = 1009.25 / 1162.2
P2 = 0.8684 atm
Here you go
This problem can be solved using one of the different gas laws, which is shown below:
PV/T
Given:
P1 = 1.1 atm
V1 = 2.5 L
T1 = 298 K
P2 = ?
V2 = 3.9 L
T2 = 367 K
Substituting the given:
P1V1/T1 = P2V2/T2
(1.1 * 2.5)/298 = (P2 * 3.9)/367
P2 = 0.868 atm
Hope it helps
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Answer: B.) 25% unchanged and 75% stable
Explanation:
Now, to calculate the initial amount of radioactive isotope
where,
a = amount of reactant left after n-half lives = 60 g
= Initial amount of the reactant = ?
n = number of half lives= 2
Putting values in above equation, we get:
Thus percentage of sample unchanged=
The percentage of sample decayed or has become stable=
Answer:
B. 25% unchanged and 75% stable
Explanation:
Edge 2021
4 J
B.
40 J
C.
400 J
D.
4000 J
The correct answer to the question is C) 400 J.
CALCULATION:
As per the question, the force applied on the block F = 40 N.
The distance travelled by the block S = 10 m.
We are asked to calculate the work done by the block.
The work done by a body under a force F is calculated as -
Work done W =
=
Here, is the angle between force and displacement.
If , then work done W =
= FS. [ cos0 = 1]
Hence, the work done by the block W = FS
= 40 N × 10 m
= 400 Joule. [ans]
Here, Joule is the unit of work.
Hence, the work done by the block s 400 Joule.
ace can you quit the smart talk and please answer in a necessary tone please fam.
Answer:
true
Explanation:
Answer:
This answer is True