TRUE OR FALSE
b.it will travel striaight line but eventually slow down
c.it will continue to speed up forever
d.it will slow down and turn
2.a car accelerates down the road .what is the reaction to the tires pushing on the road?
a.the car in the tires moving the car
b.the masses of the car pushing on the tires
c.the road pushing on the tires
d.the road moving away from the tires
Answer:
A freely falling object have fallen from a position of rest when its instantaneous speed is 10 m/s, it will travel 5.102 meter.
Explanation:
We have equation of motion, , where u is the initial velocity, u is the final velocity, s is the displacement and a is the acceleration.
In this case we have final velocity = 10 m/s, initial velocity = 0 m/s, and acceleration = 9.8 .
Substituting
A freely falling object have fallen from a position of rest when its instantaneous speed is 10 m/s, it will travel 5.102 meter.
When an object, starting from rest, achieves an instantaneous speed of 10 m/s while freely falling under gravity, it will have fallen approximately 5.10 meters.
Using the physics concept of motion under gravity, where the first equation of motion can apply (v = u + gt), your question involves finding the displacement of a freely falling object starting from rest until it reaches a speed of 10 m/s.
In this case, initial velocity (u) is zero because the object was at rest, the final velocity (v) is 10 m/s, and g is the acceleration due to gravity which is approximately 9.81 m/s².
We could rearrange the equation to find time: t = v/g = 10 / 9.81 ≈ 1.02 s. Then, we employ the second equation of motion to find the distance fallen, s = ut + 0.5gt². Since u=0, the formula simplifies to s = 0.5gt². Substituting g = 9.81 m/s² and t = 1.02 s into the equation yields s = 0.5 * 9.81 * (1.02)² ≈ 5.10 m.
Therefore, a freely falling object will have fallen approximately 5.10 meters when its instantaneous speed is 10 m/s.
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Explain the specific conditions in the area that lead to that specific type of precipitation?