The resultant of the given equation will be : y = 21
Given,
2/3y+y-4=31
Here,
First add the terms having same variable.
Add 2/3 y and y
2/3 y + y
= 5y/3
Now take -4 from LHS to RHS ,
5y/3 = 35
y = 7* 3
y = 21
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Let the first term, common difference and number of terms of an AP are a, d and n respectively.
Given that, 9th term of an AP, T9 = 0 [∵ nth term of an AP, Tn = a + (n-1)d]
⇒ a + (9-1)d = 0
⇒ a + 8d = 0 ⇒ a = -8d ...(i)
Now, its 19th term , T19 = a + (19-1)d
= - 8d + 18d [from Eq.(i)]
= 10d ...(ii)
and its 29th term, T29 = a+(29-1)d
= -8d + 28d [from Eq.(i)]
= 20d = 2 × T19
Hence, its 29th term is twice its 19th term
Answer:
Proved below.
Step-by-step explanation:
a9 = a1 + 8d = 0 where a1 = first term and d = common difference.
we need to prove that
a1 + 28d = 2(a1 + 18d
simplifying:-
a1 + 36d - 28d = 0
a1 + 8d = 0 which is what we are given.
Therefore the proposition is true.
Answer: 1.2
Why? Here:
3.6 is also known as 36/100
So, 36/100 ÷ 3/1
36/100 x 1/3 ( transposing because of divide)
36 comes in 3 table so, 36÷3 is 12
12/100 x 1
12/100 also known as 1.2
It's the same as #1 you just have to simplify x and y for w.
x + 2 = 0 | -2
x = -2
y + 3 = 0 | -3
y = -3
The 1/3 portion of 6 meters can be calculated by the concept of Division and it is come out as, 2 meter
Division is a mathematical operation, in which we distribute the number in equal parts, the number on the upper side is the total quantity and the number on the bottom side is equal parts of numbers which have to be distributed.
We denote division by '÷' this symbol.
Given that,
Length = 6 meters
one third portion of 6 meter = ?
It is known that,
Division means, dividing the number in equal parts
Like- a/b is written, it means
we have to divide number a in b equal parts,
Similarly,
It can be done in calculating one third portion of the length 6 meter,
So,
One third portion = 6/3
= 2
Hence, the one third length is 2 meter
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