3 inches
5 inches
9 inches
The required radius of the given cone is 3 inches which is the correct answer would be option (B).
The volume of a cone is defined as the amount of space occupied by a cone in a three-dimensional plane.
The volume of the cone (V )= 1/3πhr²
The volume of a cone is 141.3 cubic inches. The height of the cone is 15 inches.
To determine the radius of the given cone.
The volume of the cone (v) = 1/3πr²h
Substitute the values of h and v, solve for r
⇒ 141.3 = 1/3π(r)²(15)
⇒ 141.3 = π(r)²(5)
Divided by 5π into both sides of the above equation,
⇒ 141.3/5π = (r)²
⇒ 9 = (r)²
⇒ (r)² = 3²
⇒ r = 3
Hence, the required radius of the given cone is 3 inches.
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hexagon has 6 sides and 6 bases
Answer:
Ken has 1 of his money. He spends 1/5 so he still has 4/5 of the original amount of money. He has 4/5 and he spends $21and ends up with 1/2 of his money. 4/5 = 8/10 and 1/2 = 5/10.This means that $21 is 8/10-5/10 of his original amount of money. so $21 is 3/10 of his original amount of money. 21/3*10=70. His original amount of money is $70. This means that 1/2 of his money is $35. So Ken has $35 left.
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Step-by-step explanation:
To evaluate log3 72, given that log3 8 is approximately 1.8928, we use properties of logarithms. We can express 72 as 8×9, and since log3 9 equals 2, log3 72 is 1.8928 + 2, which is 3.8928.
The student is asking to evaluate log3 72 given that log3 8 ≈1.8928. We can use the properties of logarithms to solve this. Since 72 can be expressed as 8×9, and we know that log3 8, we can find the log3 9 by understanding that 9 is 3²and therefore log3 9 is 2, because the base and the argument are the same.
Now, using the property of logarithms that loga (xy) = loga x + loga y, we can write log3 72 as:
log3 (8 ∙9) = log3 8 + log3 9
log3 72 = 1.8928 + 2
log3 72 = 3.8928
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Answer:
≈ 3.8928
Step-by-step explanation:
log base 3 of 72 is approximately 3.8928
you would need to plug this into a calculator to solve
PART A: At a certain number of visits, both plans will cost the same. At that number, how much will both plans cost, in dollars?
PART B: Which plan is more expensive at the 10th visit?
Write the number of the plan in the box.
After 15 number of visits, both plans cost $55 and at the 10th visit, plan 2 is more expensive than plan 1.
Arithmetic sequence is a sequence of numbers where the numbers are arranged ion a definite order such that the difference of two consecutive numbers is a constant. This constant of difference is called common difference which is commonly denoted by the letter 'd'.
Part A :
From the table, we can clearly express both plans as Arithmetic sequence.
Plan 1 : First term, a = 27 and common difference, d = 2
Plan 2 : First term, a = 41 and common difference, d = 1
Let n be the number of visits that both plans costs the same.
27 + 2(n - 1) = 41 + (n - 1)
27 + 2n - 2 = 41 + n - 1
2n + 25 = n + 40
n = 15
Cost = 41 + (15 - 1) = $55
Part B :
We have to find the 10th term.
For plan 1 :
Cost at 10th visit = 27 + 2(10 - 1) = $45
For plan 2 :
Cost at 10th visit = 41 + (10 - 1) = $50
The plan 2 is more expensive at the 10th visit.
Hence at the 10th visit, plan 2 is more expensive.
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Step-by-step explanation:
From the looks of it, Plan A is 25 + 2x and plan B is 40 + x.
Part A:
25 + 2x = 40 + x
x = 15
plug in any: 40 + 15 = $55
Part B:
Plan A = $45
Plan B = $50
Plan B is $5 more expensive.