Solve by graphing
y= -4x+5
y=3x-2

Answers

Answer 1
Answer: y = -4x + 5
y = 3x - 2

  -4x + 5 = 3x - 2
+ 4x       + 4x
           5 = 7x - 2
        + 2        + 2
           7 = 7x
           7     7
           1 = x
           y = -4x + 5
           y = -4(1) + 5
           y = -4 + 5
           y = 1
     (x, y) = (1, 1)

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Rearrange the formula P = 2(l + b) for b.

Answers

b = -l + 1/2 P is the answer

115 = 5k equations and inequalities
help pl0x

Answers

Answer:

\sf{115 = 5k}

:  \implies \sf{5k = 115}

:  \implies \sf{k =   \cancel(115)/(5) }

:  \implies \sf{k = 23}

Answer: 23

Explanation:

115=5k
115/5=5/5k
23=k

Which function is graphed below? On a coordinate plane, an exponential decay function is shown. The curve starts in quadrant 2 and decreases into quadrant 1. It crosses the y-axis at (0, 3) and approaches y = 0 in quadrant 1.

Answers

The function graphed here is an exponential decay function.

Becasue an exponential decay function is characterized by a curve that starts in quadrant 2 and decreases as it moves into quadrant 1. It crosses the y-axis at a positive value and approaches y = 0 as it continues into quadrant 1. This behavior matches the description given in the question, so we can conclude that the function graphed is an exponential decay function.

The rectangle is 20 by 16 and the scale factor is 0.25. What are the dimensions of the reduced rectangle?

Answers

Answer:

1,280

The dimensions are 5 by 4

Step-by-step explanation:

You multiply 20 and 16 then, divide 0.25 then you get 1,280

Answer:1,280

Step-by-step explanation:

How do I differentiate (200000ln(t-0.1))/(39.95t^2)

Answers

f(x)=(200000\ln(t-0.1))/(39.95t^2)=(4000000)/(799)\cdot(\ln(t-0.1))/(t^2)\nf'(x)=(4000000)/(799)\cdot((1)/(t-0.1)\cdot t^2-\ln(t-0.1)\cdot2t)/(t^4)\nf'(x)=(4000000)/(799)\cdot((t)/(t-0.1)-2\ln(t-0.1))/(t^3)\nf'(x)=(4000000\left((t)/(t-0.1)-2\ln(t-0.1)\right))/(799t^3)


Answer:

\frac { dy }{ dt } =\frac { 8\cdot { 10 }^( 6 ) }{ 799{ t }^( 2 ) } \left\{ \frac { 5 }{ 10t-1 } -\frac { \ln { \left( t-\frac { 1 }{ 10 }  \right)  }  }{ t }  \right\}

Workings below. Don't know if it could've have been simplified further.

I've made a "smooth criminal" version, just in case you like things compressed.

\frac { dy }{ dt } =\frac { n }{ { t }^( 2 ) } \left\{ \frac { 1 }{ t-k } -\frac { \ln { \left( { \left( t-k \right)  }^( 2 ) \right)  }  }{ t }  \right\} \n \n n=\frac { 4\cdot { 10 }^( 6 ) }{ 799 } ,\quad k=\frac { 1 }{ 10 }

What is the product?

2x(x – 4)

Answers

Keywords:

Product, factors, polynomial, distributive property

For this case we must find the product of two factors of a polynomial. To do this, we must apply the distributive property, which states: a (b + c) = ab + ac.

So:

2x (x - 4) = 2x * x-2x * 4\n2x (x - 4) = 2x ^ 2-8x

Thus, the product of 2x (x - 4) is: 2x ^ 2-8x

Answer:

The product of 2x (x - 4) is: 2x ^ 2-8x

Answer:

The product of 2x(x- 4)=2x^2-8x

Step-by-step explanation:

Given : Expression 2x(x-4)

To find : The product of the expression

Solution :

To find the product of the expression we apply distributive property in this

Distributive propertya(b+c)=ab+ac

Where a= 2x, b=x, c=-4

2x(x- 4)=2x(x)+2x(-4)

2x(x-4)=2x^2-8x

Therefore, The product of 2x(x-4)=2x^2-8x