Answer:
Aseem’s : 8.3, Stana’s : 11.6
Step-by-step explanation:
Aseem: x
Stana: 2x-5
X+2x-5=20
3x=25
X = 8.3
The length of Aseem's car is approximately 8.33 and the length of Stana's car is approximately 11.66.
Let's define the length of Aseem's car as x. Stana's car is 5 less than 2 times the length of Aseem's car, so the length of Stana's car can be represented as 2x - 5. The sum of the lengths of both cars is 20, so we can set up the equation x + (2x - 5) = 20. Solving this equation will give us the lengths of Aseem's and Stana's cars.
Combining like terms, we get 3x - 5 = 20. Adding 5 to both sides of the equation, we have 3x = 25. Finally, by dividing both sides by 3, we find that x = 8.33.
The length of Aseem's car is approximately 8.33 and the length of Stana's car is approximately 2(8.33) - 5 = 11.66.
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Answer
40%
Explanation
A parentage value is a value that has been compared to 100.
Percentage = (change in the value)/(the original value) × 100%
= (35-25)/25 × 100%
= 10/25 × 100%
= 40%
The slope of the line 15x - 3y = 90 is 5.
The slope of a line can be determined using the equation in slope-intercept form, y = mx + b, where m represents the slope. To find the slope of the line 15x - 3y = 90, rearrange the equation to the form y = mx + b. Subtract 15x from both sides to isolate the -3y term, and then divide both sides by -3 to solve for y as a function of x. The resulting equation will be in the form y = mx + b, and the coefficient of xwill be the slope.
15x - 3y = 90
-3y = -15x + 90
y = 5x - 30
Therefore, the slope of the line 15x - 3y = 90 is 5.
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Answer:
Answer is below. Hope this helps you!
Step-by-step explanation:
(i)v = u + at
(ii) s = ut + 1/2 *at²
(iii)2as = v²-u²
Examples:
A train starting from rest attains a velocity of 72km/h in 5 minutes. Assuming that the acceleration is uniform, find (i) the acceleration and (ii) the distance travelled by the train for attaining this velocity.
72km/h = 20m/s
(i) use v= u+ at
20 = 0 + a*300
20 = 5a
20 / 300= a
1/15 ms² = a
to find distance
use 2as= v²-u²
2 *1/15 * s = (20) - 0²
2/15s = 400
s = 400 * 15/2
s = 3000m = 3 km
a car accelerates with a uniform acceleration of 1m/s². it starts with a velocity of 18km/h and reaches 36 km/h in 5 seconds find the distance travelled.
18 km /h = 5m/s
36km/h = 10m/s
use - s= ut + 1/2at²
s = 5 * 5 + 1/2 * 1 * (5)²
s = 25 + 25/2
s = 37.5 meters
Answer:
It is described in terms of displacement, distance, velocity, acceleration, time and speed. Jogging, driving a car, and even simply taking a walk are all everyday examples of motion.
...
The three equations are,
v = u + at.
v² = u² + 2as.
s = ut + ½at²