MATHEMATICS HIGH SCHOOL

| 3x | = 9
| -3r | = 9
b/5 = 1

Answers

Answer 1
Answer: |3x| = 9
|3x| = ±9
|3x| = 9    U    |3x| = -9
  3x = 9     U     3x = -9
   3     3              3      3
    x = 3               x = -3

|-3r| = 9
|-3r| = ±9
|-3r| = 9    U    |-3r| = -9
   3r = 9      U     3r = -9
    3    3               3     3
    r = 3                 r = -3

     ¹/₅b = 1
5(¹/₅b) = 5(1)
       b = 5

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Solve by elimination-3x+2y=10-2x-y=-5

Find the distance between two parallel lines: x = 11 and x = 5.

Answers

x = 11 ,\ \ \ A(11,0) \n \n x = 5 , \ \ \ B(5,0) \n \n distance \ between \ two \ parallel \ lines \ : \n \n d=\sqrt{(x_(2)-x_(1))^2 + (y_(2)-y_(1))^2}\n \nd=√((5-11)^2+(0-0)^2)=√((-6)^2)=√(36)=6
The\ distance:\n\nd=|11-5|=|6|=6

Factorise fully 9x squared - 6xy

Answers

3x(3x-2y) 

you have to find a common factor between the two numbers. in this case it's three, so you just divide each number by three.

Mentally estimate the total cost of items that have the following prices: $1.85, $.98, $3.49, $9.78, and $6.18. Round off your answers to the nearest half-dollar.

Answers

Twenty two and a half dollars
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Which of the following expresses the ratio of 3 inches to 2 yards?(A) 3 : 12
(B) 3 : 72
(C) 3 : 9
(D) 3 : 24
(E) 3 : 2

Answers

1\ yard=36\ inches\n ratio:3\ inches:2\ yards\n 2\ yards=72\ inches\n \n ratio: 3:72[inches]\n The\ correct\ answer\ is\ B.

Answer:

E

3 :2

if inhes

then D

2/3(3x-15y)+(9y-11x)

Answers

(2)/(3)(3x-15y)+(9-11x)=\n\n2x-10y+9-11x=\n\n-9x-10y+9\n\nAnswer\ is\ -9x-10y+9

The function t(x) = x + 6 determines how many cans of soup a food truck needs to stock, where x is the number of shifts the crew is going to work in the truck. The crew uses c(t(x)) to find the amount of money to spend on soup. The function c(x) = 2x + 4. Solve for how much money must be spent when the crew is going to work 4 shifts.(A. 24; B. 28; C. 30; D. 34)

Answers

Answer:

Option A is correct.

The amount of money must be spent when the crew is going to work 4 shifts is, 24

Step-by-step explanation:

Given the function:t(x) = x+6 .....[1] ; where x represents the number of shifts the crew is going to work in the truck.

Also, the crew uses c(t(x)) which  represents the amount of money to spend on soup.

The function is given as:

c(x) = 2x + 4               .....[2]

To find c(t(x)) i.e, the money must be spent when the crew is going to work 4 shifts.

⇒ x = 4

First substitute the value of x in [1] to find t(x);

t(4) = 4+6 = 10

Then;

For x=4 ,

c(t(4)) = 2(t(4)) +4                   [Using equation [2]]        

Substitute the value of t(4) = 10 we have;

c(t(4)) = 2(10) +4 = 20 + 4 = 24

Therefore, the amount must be spent when the crew is going to work 4 shifts is, 24
First, you have to solve t(x) when x=4, because the crew is working 4 scripts.    Which is t(x)=4+6                                 
t(x)=10
Then, you plug in t(x) to c(x).
c(x)=2(10)+4
c(x)=24
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