Mara carried water bottles to the field to share with her team at halftime. The water bottles weighed a total of 60x2 + 48x + 24 ounces. Which factorization could represent the number of water bottles and weight of each water bottle? 6(10x2 + 8x + 2) 12(5x2 + 4x + 2) 6x(10x2 + 8x + 2) 12x(5x2 + 4x + 2)

Answers

Answer 1

Answer: 12(5x^2+4x+2) is correct answer because divide everything by 12 and that is factorization that you get. It is the furthest simplified for of this factorization.

Answer 2

Answer:

The factorization could represent the number of water bottles and weight of each water bottle is 12.

Given that,

The water bottles weighed a total of $=60x^(2) +48x+24$ ounces.

We have to find,

The factorization could represent the number of waterbottles and weight of each water bottle.

According to the question,

The water bottles weighed a total of

$=60x^(2) +48x+24$

Taking 12 as the highest common factor gives:

$= 12 (5x^(2) + 4x+2)$

Where 12 is the number of bottles and $(5x^(2) + 4x+2)$ is the weight of eachone.

Hence , The factorization could represent the number of water bottles and weight of each water bottle is 12.

For more information about HCF click the link given below.

brainly.com/question/17240111

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. Use the process outlined in the lesson to approximate the number 3√10. Use the approximation √10 ≈3162 277 7.. Find a sequence of five intervals that contain 3√10 whose endpoints get successively closer to 3√10. Write your
iintervals in the form 3^???? < 3^√10 < 3^s for rational numbers ????and s.

Answers

Answer:

sequence of five intervals

(1) 3³ < $3^(√(10) )$ < $3^(4)$

(2) $3^(3.1)$ < $3^(√(10) )$ < $3^(3.2)$

(3) $3^(3.16)$ < $3^(√(10) )$ < $3^(3.17)$

(4) $3^(3.162)$ < $3^(√(10) )$ < $3^(3.163)$

(5) $3^(3.1622)$ < $3^(√(10) )$ < $3^(3.1623)$

Step-by-step explanation:

as per question given data

√10 ≈ 3.162 277 7

to find out

sequence of five intervals

solution

as we have given that √10 value that is here

√10 ≈ 3.162 277 7 ........................1

when we find $3^(√(10) )$ ................2

put here √10 value in equation number 2

we get $3^(√(10) )$ that is 32.27

sequence of five intervals

(1) 3³ < $3^(√(10) )$ < $3^(4)$

(2) $3^(3.1)$ < $3^(√(10) )$ < $3^(3.2)$

(3) $3^(3.16)$ < $3^(√(10) )$ < $3^(3.17)$

(4) $3^(3.162)$ < $3^(√(10) )$ < $3^(3.163)$

(5) $3^(3.1622)$ < $3^(√(10) )$ < $3^(3.1623)$

Draw or write to explain why 1 hundred 4 tens and 14 tens name the same amount

Answers

Solving the expressions, we find 140 = 140, thus, they are the same amount.

--------------------------

One hundred is 1 multiplied by 100, thus $1 * 100 = 100$
4 tens is 4 multiplied by 10, thus $4 * 10 = 40$
1 hundred 4 tens is $100 + 40 = 140$

--------------------------

14 tens is 14 multiplied by 10, thus $14 * 10 = 140$
Applying the multiplications, that is, solving the expressions, we get the same amount, this is why the measures are the same amount.

A similar problem is given at brainly.com/question/20742606

1 hundred can also be 10 tens so when you add 10 tens and 4 tens you 14 tens and that is the same thing as 14 tens

Are there any maths genius here can help?

Answers

Answer:

1 》let equal side be X and other side y

now, length of y= 2x sin teta/2

=12.3×sin42/2

=12.3 × sin21

=4.407

A midwestern music competition awarded 35 ribbons. The number of blue ribbons awarded was 3 less than the number of white ribbons. the number of red ribbons was 2 more than the number of white ribbons. How many of each kind of ribbon was awarded....white?, blue?, red?

Answers

35 total ribbons

x = white ribbons
x-3 = blue ribbons
x+2 = red ribbons

35= x+x-3+x+2
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12 = x
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9 blue ribbons
14 red ribbons

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White 12
Blue 9
Red 14
I did it without paper so I'm not sure but it works :D

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Answers

Answer: C

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