Answer:
Final answer:
To have $3000 in the savings account after 3 years, you should deposit $2688.97 for situation a, $2669.29 for situation b, and $2667.99 for situation c.
Explanation:
To find the amount you should deposit for each situation, we can use the formula for compound interest:
A = P(1 + (r/n))^(nt)
where A is the final amount, P is the principal amount (the initial deposit), r is the annual interest rate (in decimal form), n is the number of times interest is compounded per year, and t is the number of years.
Using the given information, we can calculate:
- For situation a (3% annual interest compounded quarterly), we have A = $3000, r = 3% = 0.03, n = 4 (since interest is compounded quarterly), and t = 3. Rearranging the formula, we get:
P = A / (1 + (r/n))^(nt) = $3000 / (1 + (0.03/4))^(4*3) = $2688.97 (rounded to two decimal places). - For situation b (2.25% annual interest compounded monthly), we have A = $3000, r = 2.25% = 0.0225, n = 12 (since interest is compounded monthly), and t = 3. Substituting these values into the formula, we get:
P = A / (1 + (r/n))^(nt) = $3000 / (1 + (0.0225/12))^(12*3) = $2669.29 (rounded to two decimal places). - For situation c (2% annual interest compounded daily), we have A = $3000, r = 2% = 0.02, n = 365 (since interest is compounded daily), and t = 3. Plugging these values into the formula, we get:
P = A / (1 + (r/n))^(nt) = $3000 / (1 + (0.02/365))^(365*3) = $2667.99 (rounded to two decimal places).
Learn more about Compound interest here:
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