Nick has 189 trading cards. Kyle has 198 trading cards. Who has fewer cards ?

Answers

Answer 1

Answer: Nick has fewer cards Kyle 198- 189 that Nick has = Nick has 9 less trading cards

Answer 2

Answer: Nick has fewer trading cards. 189 < 198; there is a difference of 9.

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1.What basic trigonometric identity would you use to verify that cot x sin x = cos x? . . a. cos^2x+sin^2x=1.
b. cot x= cosx/sinx.
c. cos x= 1/sec x.
d. sin x= 1/csc x. .
2.What basic trigonometric identity would you use to verify that sin^2x+cos^2x/cosx= sec x?.
a. sin x=1/csc x.
b. 1+cot^2x=csc^2x.
c. cos^2x+sin^2x=1.
d. cos x= 1/sec x

Answers

1 ) cot x * sin x = cos x
(cos x / sin x) * sin x = cos x
cos x = cos x
Answer: B ) cot x = cos x / sin x
2 ) ( sin² x + cos² x ) / cos x = sec x
1/cos x = sec x
sec x = sec x
Answer: C ) cos² x + sin² x = 1

Answer:

Step-by-step explanation:

Trig help (Problems already solved)?The calculation for the problems are already done but I have to list a reason or what is being done in each step. "Each = and newline made" means a place I have to write what is being done in the calculation.

1. (secx + sinx)cotx = cscx + cosx
=(secx + sinx)cotx = cscx + cosx
=(1 / sinx) + cosx
=cscx + cosx

2. cosx + tanx sinx = secx
=cosx + tanx sinx = cosx + (sinx / cosx)sinx
=cosx + (sin^2x / cosx) = (1 / cosx)(cos^2x + sin^2x)
=1 / cosx
=secx

3. cscx - cosx cotx = sinx
=cscx - cosx cotx = (1 / sinx) - cosx(cosx / sinx)
=(1 / sinx) - (cos^2x / sinx)
=(1 - cos^2x) / sinx
=sin^2x / sinx = sinx

4. (cosx / (1 + cosx)) + (cosx / (1 - cosx)) = 2cotx cscx
=(cosx / (1 + cosx)) + (cosx / (1 - cosx)) = ((cosx (1 - cosx) + cosx (1 + cosx))) / (1 + cosx)(1 - cosx)
=(cosx - cos^2x + cosx + cos^2x) / (1 - cos^2x)
=2cosx / sin^2x
=2(cosx / sinx)(1 / sinx) = 2cotx cscx

Thank you to whoever decides to help me with explaining what is happening on each line.

Answers

The first identity uses the definition of the reciprocal functions $\sec x,\csc x,\cot x$ and the distributive property of multiplication.

$(\sec x+\sin x)\cot x=\left(\frac1{\cos x}+\sin x\right)(\cos x)/(\sin x)$
$=(\cos x)/(\cos x\sin x)+(\cos x\sin x)/(\sin x)$
$=\frac1{\sin x}+\cos x$
$=\csc x+\cos x$

The second uses the definition of $\tan x$ and the distributive property. Then a factor of $\frac1{\cos x}$ is pulled out, which allows you to use the identity $\sin^2x+\cos^2x=1$ .

$\cos x+\tan x\sin x=\cos x+(\sin x)/(\cos x)\sin x$
$=\cos x+(\sin^2x)/(\cos x)$
$=(\cos^2x)/(\cos x)+(\sin^2x)/(\cos x)$
$=\frac1{\cos x}\left(\cos^2x+\sin^2x\right)$
$=\frac1{\cos x}*1$
$=\frac1{\cos x}$
$=1$

The third uses the same ideas as the second: rewrite the reciprocal functions, then invoke the Pythagorean identity $\sin^2x+\cos^2x=1$ , which is equivalent to $\sin^2x=1-\cos^2x$ .

$\csc x-\cos x\cot x=\frac1{\sin x}-\cos x(\cos x)/(\sin x)$
$=\frac1{\sin x}-(\cos^2x)/(\sin x)$
$=\frac1{\sin x}\left(1-\cos^2x\right)$
$=\frac1{\sin x}\sin^2x$
$=(\sin^2x)/(\sin x)$
$=\sin x$

In the last one, you combine the fractions by enforcing common denominators. This lets you add the numerators together, and the denominator can be simplified. Once you do that, you rewrite the factors of cos and sin in the numerator and denominator to make up the cot and csc functions, and you're done.

$(\cos x)/(1+\cos x)+(\cos x)/(1-\cos x)=(\cos x(1-\cos x))/((1+\cos x)(1-\cos x))+(\cos x(1+\cos x))/((1-\cos x)(1+\cos x))$
$=(\cos x(1-\cos x)+\cos x(1+\cos x))/((1-\cos x)(1+\cos x))$
$=(\cos x(1-\cos x+1+\cos x))/(1-\cos^2x)$
$=(2\cos x)/(\sin^2x)$
$=2(\cos x)/(\sin x)\frac1{\sin x}$
$=2\cot x\csc x$

At the local pet store, zebra fish cost $1.85 each and neon tetras cost $2.10 each. If Yumi bought 11 fish for a total cost of $21.60, not including tax, how many of each type of fish did she buy?A 7 zebra fish, 4 neon tetras
B 4 zebra fish, 7 neon tetras
C 6 zebra fish, 5 neon tetras
D 5 zebra fish, 6 neon tetras

Answers

Answer: C. 6 zebra fish, 5 neon tetras. Is $21.60

Step-by-step explanation:

1.85 • 6 = 11.10

2.10 • 5 = 10.50

11.10 + 10.50 = 21.60

$21.60

PLEASE HELP! GEOMETRY. The circle design is based on twelve equally spaced points placed around the circumference of the circle. As the group lays out the design, the measure of angle GAH is ____ degrees, to the nearest degree.