Luke saves 10p coins and 20p coins he has 3 times as many 10p coins as 20p coins a total of 17 pounds how 10p coins does he have ?
Answers
Answer:
10p coins does he have 102
Step-by-step explanation:
given data
saves= 10p coins and 20p coins
total = 17 pounds
to find out
how 10p coins does he have
solution
we consider here no of 20p coin = x
so equation will be here
3 × 10 x +20 x = 1700
30 x + 20 x = 1700
x = 34
so that
10p coins = 3 time × 34 = 102
20p coins = 34
so that 10p coins does he have 102
Answer:
I'm not sure how euros work but I'm almost certain there are 18 20p coins
Step-by-step explanation:
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Is the following relation a function?two ovals, one labeled x and the other labeled y. The negative 2 in the x oval is pointing to the 5 in the y oval, the 0 in x is pointing to 1 and 3 in y, 5 in x pointing to 8 in y, and 7 in x pointing to 5 in y Yes No
Answers
Answers
Answer:
To evaluate the given expressions, we need to follow the order of operations, also known as PEMDAS (Parentheses, Exponents, Multiplication and Division from left to right, Addition and Subtraction from left to right). Let's simplify each expression step by step:
1. 8 + 6:
The addition operation is straightforward. Adding 8 and 6 gives us the answer of 14.
2. 12 - 2.6:
Again, we perform the subtraction operation. Subtracting 2.6 from 12 gives us the answer of 9.4.
3. 28 + 7.4:
Similar to the first expression, we add 28 and 7.4 to get the answer of 35.4.
Therefore, the simplified expressions are as follows:
- 8 + 6 = 14
- 12 - 2.6 = 9.4
- 28 + 7.4 = 35.4
Step-by-step explanation:
Answers
Hope this helps:)
Answers
Answer: angle AOB = 40 degrees
====================================================
Explanation:
The smaller angles AOB and BOC combine to the largest angle AOC
By the angle addition postulate, we can say,
(angleAOB) + (angleBOC) = (angleAOC)
(3x+4) + (8x-28) = 108
11x-24 = 108
11x = 108+24 .... adding 24 to both sides
11x = 132
x = 132/11 .... dividing both sides by 11
x = 12
We can use this x value to find each angle
angle AOB = 3x+4 = 3*12+4 = 40 degrees
angle BOC = 8x-28 = 8*12-28 = 68 degrees
As a check,
(angleAOB)+(angleBOC) = (40)+(68) = 108
which matches with the measure of angle AOC. This confirms our answers.
Answer:
Step-by-step explanation:
Answers
With the Brainly help you've gotten in the last 15 minutes or so,
you should be able to do this one now.
The mystery number . . . . . . . M
Half of it . . . . . . . . . . . . . . . . 1/2 M
Half of it decreased by 8 . . . 1/2 M - 8
You said that's 3 .
So the equation you have to solve is
1/2 M - 8 = 3
Add 8 to each side: 1/2 M = 11
Multiply each side by 2 : M = 22
This is easier than the last one we ( I ) did.
Answers
x | p(x) = -16x^2+32x
--------------------------
1 | p(1) = -16(1)^2 + 32(1) = 16
2 | p(2) = -16(2)^2 + 32(2) = 0
Having obtained the desired result at x = 2, this means that the model rocket has been in the air for 2 seconds.
Final answer:
The model rocket is in the air for 0 seconds according to the given equation, which implies an immediate impact upon launch.
Explanation:
In this mathematical scenario, the model rocket's height p(x) over time x (elapsed seconds) is given by the quadratic equation p(x) = 16x^2 + 32x. The total amount of time the rocket is in the air will be the point when the rocket returns to ground level. This occurs when p(x) = 0, which represents the rocket's height being zero feet above the ground.
We can find out when this occurs by solving the quadratic equation for x. We can rearrange the quadratic equation to 16x^2 + 32x = 0. Factoring out 16x gives us 16x(x + 2) = 0. Solving for x will give two potential solutions: x = 0 (the initial launch point) and x = -2. However, since time cannot be negative in this context, we discard the -2 and our answer is x=0 s, the total time the model rocket will be in the air after being launched is 0 seconds.
Learn more about Quadratic Equations here:
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