MATHEMATICS HIGH SCHOOL

Cosx-Cos2x=0
Solve. I'm not sure if I'm getting the right answers

Answers

Answer 1
Answer: cos(2x)= 2cos^2(x)-1\n \n cos(x)-cos(2x)=0 \n cos(x)-(2cos^2(x)-1)=0 \n -2cos^2(x)+cos(x)+1=0 \n 2cos^2(x)-cos(x)-1=0 \n (2cosx+1)(cosx-1)=0 \n \n 2cos(x)+1=0 \n cos(x)= - (1)/(2) \n x= \pm arccos(- (1)/(2) )+2 \pi k~~~k\in Z \n arccos(- (1)/(2) )= (2 \pi )/(3) \n x=\pm (2 \pi )/(3)+2 \pi k~~~k\in Z \n \n


cos(x)-1=0 \n cos(x)=1 \n x= 2\pi k~~~k \in Z

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Answers

You would use point slope form
y+1=-7(x-4)
y=-7x+27

Y = –x + 4
x + 2y = –8
How many solutions does this linear system have?

Answers

y = - x + 4
x + 2 ( -x + 4 )=-8
x- 2 x + 8 = -8
- x = - 8 - 8 
- x = - 16
x = 16
y = - 16 + 4
y = - 12
The system has one solution ( x, y ) = ( 16, - 12 ).

Answer:

Step-by-step explanation:

Y = –x + 4

x + 2y = –8

How many solutions does this linear system have

one solution: (8, 0)

one solution: (0, 8)

no solution

infinite number of solutions

Round 82290 times 240

Answers

19,749,600 is the correct answer. according to calculator

What is the polynomial function of lowest degree with lead coefficient 1 and roots i, –2, and 2?f(x) = x4 – 3x2 – 4
f(x) = x3 + x2 – 4x – 4

Which second degree polynomial function has a leading coefficient of –1 and root 4 with multiplicity 2?
f(x) = –x2 – 8x – 16
f(x) = –x2 + 8x – 16
f(x) = –x2 – 8x + 16

Which polynomial function has a leading coefficient of 1 and roots 2i and 3i with multiplicity 1
f(x) = (x + 2i)(x + 3i)
f(x) = (x – 2)(x – 3)(x – 2i)(x – 3i)
f(x) = (x + 2i)(x + 3i)(x – 2i)(x – 3i)

Answers

In the question "What is the polynomial function of lowest degree with lead coefficient 1 and roots i, –2, and 2?" The given roots are i, -2 and 2. Recall that for any polynomial having complex root, the conjugate of the complex root is also a root of the polynomial, thus -i is also a root of the required equation. Thus the required equation is obtainrd thus: f(x) = (x - i)(x + i)(x - 2)(x + 2) = (x^2 + 1)(x^2 - 4) = x^4 - 4x^2 + x^2 - 4 = x^4 - 3x^2 - 4 In the question "Which second degree polynomial function has a leading coefficient of –1 and root 4 with multiplicity 2?" The required equation is obtained thus: f(x) = -(x - 4)^2 = -(x^2 - 8x + 16) = -x^2 + 8x - 16 In the question "Which polynomial function has a leading coefficient of 1 and roots 2i and 3i with multiplicity 1" Recall that for any polynomial having complex root, the conjugate of the complex root is also a root of the polynomial, thus -2i and -3i are also roots of the required equation. Thus the required equation is obtained thus: f(x) = (x + 2i)(x + 3i)(x - 2i)(x - 3i).

List the factors of 5i^2+12i−32 i need help fast

Answers

Answer:

Step-by-step explanation:

5i² + 12i - 32i  = 5i² - 20i

                      = 5i² - (5*4*i)

                      = 5i(i - 4)

Terrance and his family are planning how to pay for his college education. The cost of tuition at his chosen college is $14,500 per year. Terrance's parents will pay 80% of the tuition cost every year and he will pay the rest. Terrance has two years to save enough money to attend his first year of college. What is the minimum amount he should save every month in order to reach his goal? PLZ REPLY ASAP!

Answers

Answer:

terrence will have to play 2900

Step-by-step explanation:

80% * 14500

14500-11600

2900

80% of 14500 = 11600

14500-11600=2900

He needs to save 2900 a month
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