2x^2 + x – 1 = 9
Does it have any real solutions? If so what are they?

Answers

Answer 1

Answer: $2x^2 + x - 1 = 9 \n \n2x^2 + x -1 - 9=0\n \n2x^2 + x-5x +5x -10 = 0 \n \n 2x^2 -4x +5x -10 = 0\n \n 2x(x -2) +5(x -2) = 0\n \n(x-2)(2x+5)=0\n \nx-2 =0 \ \ or \ \ 2x+5 =0 \n \nx=2 \ \ or \ \ 2x =-5 \n \nx=2 \ \ or \ \ x =-(5)/(2) \n \nAnswer : \ x=2 \ \ or \ \ x=-(5)/(2)$

Answer 2

Answer: 2x^2 + x – 1 = 9
2x^2+x-1-9=0
2x^2+x-10=0
a=2
b=1
c=-10

Delta=b^2-4ac
Delta=1-4*2*(-10)
delta=1+80
delta=81
rad 81=9

x1=-b-rad 81 /2a
x1=-1-9/2*2
x1=-10/4
x1=-5/2

x2=-b+rad 81 /2a
x2=-1+9/2*2
x2=8/4
x2=2

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Marneshia walked three over eight of a mile in three over five of an hour. What equation can be used to calculate her unit rate in miles per hour?

Answers

3/8 mile in 3/5 hour
$( (3)/(8) )/( (3)/(5) )$
we want to find miles per hour or m/1h
convert 3/5 to 1 by multiplying it by 5/3
keep the fraction the same by multiply ing the whole thing by
$( (5)/(3) )/( (5)/(3) )$ to get

$( (15)/(24) )/( (15)/(15) )$ =
$( (5)/(8) )/( 1)$ =5/8 miles per hour

Answer:

3/8 mile in 3/5 hour

Step-by-step explanation:

I am taking the test right now

Solve the linear equation x+x+2+x+4+x+6=-28
help!!!!!!!!!!!!!!! show work

Answers

$x+x+2+x+4+x+6=-28\n\n4x+12=-28\ \ |\ subtract\ 12\ to\ both\ sides\n\n4x=-28-12\n\n4x=-40\ \ | \ divide \ both \ sides\ by\ 4\n\nx=-10$

$x+x+2+x+4+x+6=-28\n4x=-40\nx=-10$

To manage a rental property a property manager charges $59 per month plus 8%of rent

Answers

A property manager charges = $59.

Rent is = 8% of rent.

Let us assume rent is = $ r per month.

Therefore, 8% of r would be 0.08 r.

Now, the total monthly fees charged by the property manager = Fix charge + 8% of rent.

Let us take total montly charge by T.

Therefore, we can setup an equation:

T = 59 + 0.08r.

Therefore, T = 59 + 0.08r is the equation to represent the total monthly fees charged by the property manager.

Ayesha has a theory about two digits numbers that have a larger tens digit then ones digit.she says that reversing the digits and subtracting the reversed number from the original number will always generate a number that is multiple of 9.is ayesha right?if so why do you think this works?if not,why not?

Answers

Answer:

Yes she is right

Step-by-step explanation:

Given that Ayesha has a theory about two digits numbers that have a larger tens digit then ones digit.she says that reversing the digits and subtracting the reversed number from the original number will always generate a number that is multiple of 9.

The reason is as follows: Let x be in 10th digit and y be in unit digit.

x>y

10x+y will be the place value.

If reversed we have 10y+x would be the value of the number

Difference would be

$10x+y-(10y+x)\n=9x-9y\n=9(x-y)$

Hence this has to be a multiple of 9.

Yes she is right. It works because the sum of the individual digits of the difference is divisible by nine.

The square abcd has side length 10cm. E is the midpoint of BC. Work out the length of DE. Answer to 1 decimal place.

Answers

-- DEC is a right triangle.

-- DC is one side of the square = 10 cm
-- EC is half the side of the square = 5 cm
-- DE is the hypotenuse = square root of (5² + 10²) = √(125 cm²) .

-- Truncated to one decimal place, that's 11.1 cm.

-- Rounded to one decimal place, it's 11.2 cm.

Think of it as a triangle. E is the midpoint of BC, so EC is 5cm. Then CD is 10cm. Pythagoras it, so 5^2 + 10^2 = DE^2. Rt(125) = 11.2 to 1 decimal place. That's the answer

Shawn has $3 more than twice as much money as Peter.If Shawn has $10, how muchmoney does Peter have.