Being rejected by a peer group can negatively influence one's self-esteem.
Answers
Explanation:
This is true that being rejected by a peer group can negatively influence one's self-esteem.
This is because when a person gets rejected then he himself develops an image that there might be something bad in me that is why people don't like me.
And when this rejection exceeds to an extent then there might be possibility that the person will become irritated and arrogant. Then he must be willing that whatever he wants he should have it no matter if it is legal or illegal according to him.
So, basically reject from people can lead to hatred, negative feelings, disappointment or dejection into a person.
Related Questions
Any substance that yields a hydrogen ion when placed in a water solution is called a(n) _____.
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The total energy of a 0.050 kg object travelling at 0.70 c is:A) 2.10 × 107 J B) 3.06 × 107 J C) 2.46 × 1015 J D) 6.30 × 1015 J E) 8.82 × 1015 J
Hardness is indirectly related to: specific gravity surface roughness strength of chemical bonds weight
A) 10 Ω
B) 15 Ω
C) 20 Ω
D) 55 Ω
Answers
Answer:
Resistor R₃ = 10 Ω
Explanation:
It is given that,
Current flowing in the circuit, I = 2 A
Resistors R₁ = 2 Ω
Resistor R₂ = 3 Ω
Voltage, V = 30 V
We have to find the value of R₃. All three resistors are connected in series. In series combination, the current flowing through the all resistors is same. Firstly, calculating equivalent resistance of three resistors as :
..............(1)
Using Ohm's law :
On solving above equation :
Hence, the correct option is (A) " 10 Ω "
The value of R3 is A) 10 Ω
Answers
(b) On wet concrete.
(c) On ice, assuming that μs = 0.100 , the same as for shoes on ice.
Answers
Final answer:
The maximum acceleration of a car moving uphill can be calculated using the formula μs*g*cosθ - g*sinθ where θ is the slope angle, μs is the coefficient of static friction, and g is the acceleration due to gravity. The figures for μs differ depending on the road condition - dry concrete, wet concrete, or ice, substantially affecting the car's acceleration.
Explanation:
The maximum acceleration of a car moving uphill is determined by the force of static friction, which opposes the combined force of the car's weight component down the plane and the force utilized by the driving wheels. The maximum static friction force (F_max) is determined by the coefficient of static friction (μs) multiplied by the normal force (N), which is equivalent to the weight of the car (mg) multiplied by the cosine of the angle (cosθ).
(a) On dry concrete: Since the μs is usually 1.0 on dry concrete and half the weight of the car is supported by the drive wheels, the maximum acceleration can be calculated as μs*g*cosθ - g*sinθ
(b) On wet concrete: The μs is around 0.7 on wet concrete. Substituting this value into the formula would give us the maximum acceleration on a wet surface.
(c) On ice: With a μs value of 0.1 as given, the maximum acceleration on ice can also be calculated using the same formula.
As one can see, the road conditions significantly impact the car's maximum acceleration due to the change in the amount of friction between the tires and road surface.
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Final answer:
The maximum accelerations for the car going up a 4º slope are 9.3 m/s² on dry concrete, 6.4 m/s² on wet concrete, and -0.1 m/s² on ice.
Explanation:
The maximum acceleration of the car up the slope can be calculated using the equation: a = μs * g * cosθ - g * sinθ, where a is the acceleration, μs is the coefficient of static friction, g is the acceleration due to gravity, and θ is the angle with the horizontal.
To solve this problem, we must teach the student to take several factors into account, including the various coefficients of static friction corresponding to different road conditions, namely dry concrete, wet concrete, and ice.
Considering that each scenario has different values of μs, we fill in the equation with the angles and coefficients of static friction. As a rule of thumb, μs for dry concrete is generally taken as 1.0, for wet concrete as 0.7 and for ice (mentioned in the question) as 0.100.
- For dry concrete, a = 1.0 * 9.8 * cos(4) - 9.8 * sin(4) = 9.3 m/s².
- For wet concrete, a = 0.7 * 9.8 * cos(4) - 9.8 * sin(4) = 6.4 m/s².
- For ice, a = 0.100 * 9.8 * cos(4) - 9.8 * sin(4) = -0.1 m/s².
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Answers
Vhorizontal = V · cos(angle)
In your case Vhoriontal = 16 · cos(40) = 12.3 m/s
Answer: 12.3 m/s
The approximate horizontal component of the initial velocity is 12.3 m/s
What is projectile?
When an object is thrown at an angle from the horizontal direction, the object is said to be in projectile motion. The object which follows the projectile motion.
Given is Ronnie kicks a playground ball with an initial velocity of 16 m/s at an angle of 40° relative to the ground.
The horizontal component of the projectile is
Vx= V cosθ
Substitute the values, we get
Vx = 16 cos(40) =
Vx =12.3 m/s
Thus, approximate horizontal component of the initial velocity is 12.3 m/s.
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300 J
400 J
1000 J
Answers
Answer:
The K.E of the pendulum is, K.E = 200 J
Explanation:
Given data,
The kinetic energy of the bob of the pendulum at the bottom, K.E = 600 J
The potential energy at the height 4 m, P.E = 400 J
According to the conservation of energy, the total energy of the mechanical system should be conserved.
At the bottom of the swing, the entire mechanical energy of the pendulum is purely kinetic. Therefore the total energy
E = P.E + K.E
= 0 + 600 J
= 600 J
Therefore, the total energy of the system, E = 600 J
At height 4 m, the total energy of the system remains the same.
Therefore,
600 J = 400 J + K.E
K. E = 600 J - 400 J
= 200 J
Hence, the K.E of the pendulum is, K.E = 200 J