MATHEMATICS HIGH SCHOOL

How can i simplify the square root of 49x^8?

Answers

Answer 1

Answer:

The simplifiedform of the square root of 49 $x^8$ is 7 $x^4$ .

We have,

To simplify the squareroot of 49 $x^8$ , we can break it down using the properties of square roots.

First, we can simplify the squareroot of 49, which is 7, since the square root of a perfect square is an integer.

Next, we can simplify the square root of $x^8$ .

We can rewrite $x^8$ as ( $x^4$ )².

Then, we can take the squareroot of $x^4$ , which is x².

Thus,

The simplifiedform of the square root of 49 $x^8$ is 7 $x^4$ .

Learn more about expressions here:

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Answer 2

Answer: The square root of 49 is 7, since 7*7 is equal to 49. and i don't know what u mean by "^". but if u mean the square root of 49, which is 7, multiplied by 8; then that's 56.

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A line passes through the points (1, -6) and (4,3). What is the y-intercept of this line?○ -9
○ -3
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Answers

After plugging in the points into the formula y2-y1/x2-x1, you’ll find that the slope is 3 or 3/1. Slope is written as rise over run. Using this information, you’ll see that the y-intercept is (0,-9). Hopefully I’m right and hopefully this helps!

Answer: -9

What is the answer to this

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Answer:

Step-by-step explanation:

Find the value of log 1.0125

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the answer is 0.00539503188

Twice the sum of a number and three

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the answer will be 2(x+3)

Find the midpoint of the segment with the following endpoints. (6, 4) and (9,9)

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Answer:

15/2, 13/2.

Step-by-step explanation:

Here's a graph as well.

Answer in fraction form = (15/2, 13/2)

Answer in decimal form = (7.5, 6.5)

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Explanation:

To get the midpoint, we average the two endpoint values. We handle the x and y coordinates separately.

The x coordinates of each point are 6 and 9. They average to (6+9)/2 = 15/2 = 7.5; so you add up the x coordinates and divide by 2.

The y coordinates are handled the same way. Add them to get 4+9 = 13 and then divide by 2 to get 13/2 = 6.5

The midpoint is (15/2, 13/2) = (7.5, 6.5)

Subtract a^2 - 7a + 11 from the sum of 3a^2 - 4 and 5a^2 + 6a

Answers

$3a^2-4+5a^2+6a-(a^2-7a+11)=\n 8a^2+6a-4-a^2+7a-11=\n 7a^2+13a-15$

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