The initial term of the sequence is 15. The common difference is 3, so the n-th term (an) is
... an = 15 + 3(n-1)
For n=14, the 14th term of the sequence is
... a14 = 15 + 3(14 -1) = 54
The sum of terms is the average of the first and last, multiplied by the number of terms:
... sum = (15 + 54)/2·14 = 7·69 = 483
The appropriate answer choice is
... 54; 483
11%
12%
-20%
Answer:
12%
Step-by-step explanation:
3x – y = 4
2x + y = 6
2. What is the y-coordinate of the solution to the system of equations?
5x - y = 25
4x + 3y = 1
3 . What is the x-coordinate of the solution to the system of equations?
x = y + 16
y + 4x = 9
4 . Graph the system of equations using technology.
What is the x-coordinate of the solution?
Round to the nearest hundredth.
-6x - 7y = 8
x + 5y = 11
The x-coordinates and y-coordinates of the given simultaneous equations are; as silver below.
1) To use linear combinations to solve the simultaneous equation;
3x – y = 4 ------(eq 1)
2x + y = 6 ---- (eq 2)
Add eq 1 to eq 2 to get;
5x = 10
divide both sides by 2 to get;
x = 2
Thus; 3(2) - y = 4
y = 6 - 4
y = 2
2) 5x - y = 25 ------(eq 1)
4x + 3y = 1 ----- (eq 2)
Make y the subject in eq 1 t get;
y = 5x - 25
Put 5x - 25 for y into the equation 2 to get;
4x + 3(5x - 25) = 1
4x + 15x = 76
19x = 76
x = 4
y = 5(4) - 25
y = -5
3) x = y + 16 - - - (eq 1)
y + 4x = 9 - - - (eq 2)
Put eq 1 in eq 2 to get;
y + 4(y + 16) = 9
y + 4y + 64 = 9
5y + 64 = 9
y = (9 - 64)/5
y = -11
Thus;
x = -11 + 16
x = 5
4) -6x - 7y = 8 - - - (eq 1)
x + 5y = 11 - - - (eq 2)
Make x the subject in eq 2 to get;
x = 11 - 5y
Put 11 - 5y for x in eq 1;
6(11-5y) -7y = 8
66 + 30y - 7y = 8
23y = -58
y = -2.5217
Thus;
x + 5(-2.5217) = 8
x = 8 + 12.608
x = 20.608
Read more about simultaneous equations at; brainly.com/question/16863577
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Answer:
6 cup of milk
Step-by-step explanation:
From question
for 11 cookies → of a cup of milk required
Now,
for 99 cookies
we multiply both sides by 9.
11 × 9 = × 9
for 99 cookies = 6 cup of milk
x-y=0
I have to solve by elimination.
Will someone help me please?
a. Al
b. Bi
c. Na
d. Fe