Nine times a number is three thousand six hundred what is the number?

Answers

Answer 1
Answer: The way this should be set up is: 

9a = 3600... 

So you must divide '9' on both sides, canceling out the '9', and making the 3600 to be '400'.. 

So the problem should look like: a = 400 <--- (Answer) 

Hope it helped.. :) 


Answer 2
Answer: =>Let the number be a ...=>Nine times the number: 9a ...=>Nine time a no. Is 3600 : 9a = 3600...=>9a = 3600=>a = 3600/9=>a= 400..=>So the number is 400..Hope It helps!!

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Find values of x and y for which ABCD must be a parallelogram. The diagram is not to scale.
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Answers

The answer is d. 

3x-14 = x-2     solve for x

4y-7 = y+11    solve for y
3x-14=x+2
Add 14 to both sides.
3x=x+16
Subtract x from both sides.
2x=16
Divide by 2.
x=8

4y-7=y+11
Add 7 to both sides.
4y=y+18
Subtract y from both sides.
3y=18
Divide by 3.
y=6

The answer is d.

Evaluate the expression when x = 8 and y = 1.

x/2y

Answers

Given: x/2y
Solution : 8/2(1) = 8/2 = n

Answer: 4

Answer:

Given: x/2y

Solution : 8/2(1) = 8/2 = n

Answer: 4

Step-by-step explanation:

Hope this help may i please have brainliest :)

What is the slope of the line that passes through the points (-4,4) and (-1,3)

Answers

Answer:

-1/3

Step-by-step explanation:

I’m on a timer I need help with this ASAP!!!!!!!!!!

Answers

I think 186 is the answer I believe sorry if wrong

If an object has a mass of 50 kilograms, what would it weigh on Uranus, where the acceleration due to gravity is. 10.5 meters/second2?

Answers

Mass of n object : m = 50 kg.
On Uranus : g ( Uranus ) = 10.5 m/s²
Weight = Mass   x  Acceleration due to gravity
Weight = 50 kg · 10.5 m/s² = 525 kgm/s² = 525 N

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS!!What are the factors of the polynomial function?

Use the rational root theorem to determine the factors.

Answers

Answer: (x - 2)(x + 2)(2x + 1)

Step-by-step explanation:

        q                     p

f(x) = 2x³ + x² - 8x - 4

rational root theorem: (p)/(q) = +/- (1, 2, 4)/(1, 2) so the possible roots are: +/- 1, 2, 4, (1)/(2)

Let's try x = 2

2  |   2     1     -8     -4

   |   ↓     4     10     4

       2     5     2      0   remainder is 0 so (x - 2) is a factor

0 = (x - 2)  (2x² + 5x + 2)

0 = (x - 2)  (x + 2)(2x + 1)


Answer: X - 2 ( X + 2) (2 x + 1)