C on edgenutiy just took it
Answer:
y = 80
x = 5
Hope this helped :)
Step-by-step explanation:
Lets say x + 5 so,
y = 8(5) + 12
y = 40 + 12
y = 52 so now we go back to the top equation which would be,
16(5) - 2(52) = -24
80 - 2(52) = -24
80 - 104 = -24, true
Therefore, any number you put in will still get you -24 so your answer is correct if you do substitution right.
Answer:
y = 80
x = 5
Hope this helped :)
Step-by-step explanation:
Lets say x + 5 so,
y = 8(5) + 12
y = 40 + 12
y = 52 so now we go back to the top equation which would be,
16(5) - 2(52) = -24
80 - 2(52) = -24
80 - 104 = -24, true
Therefore, any number you put in will still get you -24 so your answer is correct if you do substitution right.
-3n - 11
3n - 11
-3n + 11
3n + 11
x^2-4x+2=0
Approximately what percent of the bags of baby carrots have between 90 and 100 carrots?
Answer: 46%
Step-by-step explanation:
Since the number of baby carrots in a bag is normally distributed, we would apply the formula for normal distribution which is expressed as
z = (x - µ)/σ
Where
x = the number of baby carrots in the bag.
µ = mean
σ = standard deviation
From the information given,
µ = 94 carrots
σ = 8.2 carrots
The probability that a bag of baby carrots have between 90 and 100 carrots is expressed as
P(90 ≤ x ≤ 100)
For x = 90,
z = (90 - 94)/8.2 = - 0.49
Looking at the normal distribution table, the probability corresponding to the z score is 0.31
For x = 100,
z = (100 - 94)/8.2 = 0.73
Looking at the normal distribution table, the probability corresponding to the z score is 0.77
Therefore,
P(90 ≤ x ≤ 100) = 0.77 - 0.31 = 0.46
The percent of the bags of baby carrots that have between 90 and 100 carrots is
0.46 × 100 = 46%
x - 2y + 3z = 7
x + 2y - 5z = -21
a)(2, 3, 5)
b)(-2, 3, 5)
c)(2, -3, 5)
d)(2, -3, 5)