MATHEMATICS HIGH SCHOOL

Frankie paid $11.75 for the movie ticket and $4.75 for popcorn and a drink. How much did Frankie spend?
a. $7.00
b. $15.50
c. $15.75
d. $16.50

Answers

Answer 1
Answer: He spent $16.50. Add the two amounts up.
Answer 2
Answer:

Its 16.50

11.75 + 4.75

add them and you have your answer :) hope that helped

Related Questions

Help asap please !!!
Simplify (3+4i) +(5-2i)
Which calculations could be used to solve this problem? There are 21 children at Corie's party. There are 2 times as many girls as boys at the party. How many girls are at the party? Choose all answers that are correct. A. Multiply 21 × 2. Divide the product by 3. B. Add 21 + 2. Divide the sum by 3. C. Divide 21 ÷ 3. Subtract the quotient from 21. D. Divide 21 ÷ 3. Multiply the quotient by 2.
Sally earns graduated commission on her sales each month. She earns 6% commission on the first $45,000 in sales and 8% on anything over that. If Sally had $51,000 in sales this month, how much commission did she earn?
Muriel says she has written a system of two linear equationsat has an infinite number of solutions One of the equationsof the system is 3y 2x 9. Which could be the otherequation?

Let f(x)=x^2 - 16. find f^-1(x).

Answers

f(x)=x^2-16\n\ny=x^2-16\n\nx^2=y+16\n\nx=√(y+16)\n\nf^(-1)(x)=√(x+16)
A quadratic function doesn't have inverse function. But you can find inverse function for each of its "arms".

f(x)=x^2-16 \Rightarrow x_(vertex)=0\n y=x^2-16\n x^2=y+16\n x=-√(y+16) \vee x=√(y+16)\n f^(-1)(x)=-√(x+16) \hbox{ for } x<0\hbox{ (left arm)}\n f^(-1)(x)=√(x+16) \hbox{ for } x>0\hbox{ (right arm)}

Examples of prime numbers

Answers

1,2,3,5,7,11.... Any number that are only divisible by 1 and the number itself

The sum of the first 10 terms of an arithmetic sequence is 235 and thesum of the second 10 terms is 735. Find the first term and the common

difference.

Answers

If the sum of the first 10 terms of an arithmetic sequence is 235 and the sum of the second 10 terms is 735. The first term of the arithmetic sequence is -21.5 and the common difference is 10.

What is the arithmetic sequence?

Let's a represent the first term of the arithmetic sequence and the common difference as d

Formula for the sum of the first n terms of an arithmetic sequence is given by:

S_n = (n/2) * [2a + (n - 1)d]

So,  

Sum of the first 10 terms: S₁₀ = 235

Sum of the second 10 terms: S₂₀ = 735

First 10 terms:

S₁₀ = (10/2) * [2a + (10 - 1)d]

235 = 5 * [2a + 9d]

47 = 2a + 9d

Second 10 terms:

S₂₀ = (10/2) * [2a + (20 - 1)d]

735 = 5 * [2a + 19d]

147 = 2a + 19d

Now we have a system of equations:

2a + 9d = 47

2a + 19d = 147

(2a + 19d) - (2a + 9d) = 147 - 47

10d = 100

d = 10

Substitute it into the first equation to solve for "a":

2a + 9(10) = 47

2a + 90 = 47

2a = -43

a = -21.5

Therefore the first term of the arithmetic sequence is -21.5 and the common difference is 10.

Learn more about arithmetic sequence here:brainly.com/question/6561461

#SPJ3

Answer:

             \bold{a_1 = -42.65}\n\n\bold{d=14.7}

Step-by-step explanation:

The sum of the first 10 terms of an arithmetic sequence is:

S_(10)=a_1+a_2+...+a_(10)=(a_1+a_(10))/(2)\cdot10=(2a_1+(10-1)d)/(2)\cdot10

(2a_1+(10-1)d)/(2)\cdot10=235\n\n(2a_1+9d)\cdot5=235\n\n2a_2+9d=47

the  sum of the second 10 terms is:  a₁₁ + a₁₂+...+ a₂₀

And the sum of the first 20 terms of an arithmetic sequence is:

S_(20)=a_1+a_2+...+a_(10)+a_(11)+...+a_(20)=(2a_1+(20-1)d)/(2)\cdot10

so the  sum of the second 10 terms is:

a_(11)+a_(12)+...+a_(20)=S_(20)-S_(10)

Therefore we have:

(2a_1+(20-1)d)/(2)\cdot10-(2a_1+(10-1)d)/(2)\cdot10=735\n\n(2a_1+19d)\cdot5-(2a_1+9d)\cdot5=735\n\n2a_1+19d-(2a_1+9d)=147\n\n10d=147\n\nd=14.7

and:  

2a_1+9\cdot14.7=47\n\n2a_1+132.3=47\n\n2a_1=-85.3\n\na_1=-42,65

Two sides of a right triangle have the lengths 4 and 5. What is the product of the possible lengths of the third side? Express the product as a decimal rounded to the nearest tenth.

Answers

Answer:

19.2

Step-by-step explanation:

1st Case:

4 and 5 are legs of the right triangle.

Using the pythagorean therom: a^2+b^2=c^2

We can say that 4^2+5^2=x^2

16+25=x^2

41=x^2

x=√41

√41 is about 6.4

x=6.4

2nd Case

5 is the hypotenuse of the right triangle and 4 is the legs.

Using the pythagorean therom: a^2+b^2=c^2

We can say that 4^2+x^2=5^2

16+x^2=25

x^2=9

x=3

Final Step

We need to multiply the two possible lengths for x. So for case 1 the length of x was 6.4 and for case two the length was 3. 6.4*3=19.2

Anwser: 19.2

Which of these geometric terms best describes railroad tracks?

Answers

Gee, there's nothing to choose from.  I'd guess parallel lines.

Can somemone help with this one with an explination its one question

Answers

What question is it bro/sis?
Other Questions
6r+7=13+7r how do you solve this?
What is the probability of someone correctly guessing your Social Security number? (Assume all digits 0-9 are available for use)a
What is the sum of the exterior angle measures for a regular pentagon?
Find the GCF of 44j5k4 and 121j2k6.Find the GCF of 44 and 121. Find the GCF of j5 and j2. Find the GCF of k4 and k6. What is the GCF of 44j5k4 and 121j2k6? 4j3k2 4j2k4 11j3k2 11j2k4 (this is the correct one)