Its very simple\
To find the values of x2 and y2 for point G(0,0) when you are given that G is the midpoint of points (x1, y1) and (x3, y3), you can use the midpoint formula:
Midpoint formula:
(x, y) = ((x1 + x3) / 2, (y1 + y3) / 2)
Given:
(x1, y1) = (2, 3)
G(0, 0)
Plug these values into the midpoint formula:
(0, 0) = ((2 + x3) / 2, (3 + y3) / 2)
Now, solve for x3 and y3:
For x3:
0 = (2 + x3) / 2
Multiply both sides by 2 to isolate x3:
0 = 2 + x3
Subtract 2 from both sides to find x3:
x3 = -2
For y3:
0 = (3 + y3) / 2
Multiply both sides by 2 to isolate y3:
0 = 3 + y3
Subtract 3 from both sides to find y3:
y3 = -3
So, the values are:
x3 = -2
y3 = -3
Therefore, the coordinates for point (x2, y2) are:
x2 = 3
y2 = -3
48x +68 = 8 (B1 + 9x +12)
what do I do from there????????????????? the question is asking to solve for Base 1/ B1
A=(1/2)(b1+b2)h =
=(48x+68)in² = (1/2)( b1+(9x+12))8
=b1= 3x+5
Answer:
a. Equation is 3x - 2y = 0
b. x = 6 and y = 9
Step-by-step explanation:
a.
Given that
The Weight of the square is y
And, the weight of the triangle is x
Now the equation according to the attached diagram is
x + 3y = 4x + y
4x - x + 3y - y = 0
3x - 2y = 0
b.
Now if x = 6
So, y would be
3x - 2y = 0
3x = 2y
3(6) = 2y
18 = 2y
y = 9
We simply applied the above equation so that the correct value could come
And, the same is to be considered
The equation x + y = x + y represents the hanger with the weights of the triangle and square. When x is 6, y can be any value.
The question asks for an equation to represent the hanger with the weights of the triangle and square. Since the weight of the triangle is represented by x and the weight of the square is represented by y, the equation can be written as x + y = x + y. This equation shows that the sum of the weights on each side of the hanger is equal.
To find the value of y when x is 6, we can substitute the value of x into the equation. x + y = 6 + y. By subtracting y from both sides, we get x = 6. Therefore, when x is 6, y can be any value since it cancels out from both sides of the equation.
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of its previous height. What height
will it reach after the third bounce?
Answer:
1.7342 m
Step-by-step explanation:
in order to find this, we need to find what 2 thirds of 6 is. The answer to that is 4, because 2/3 can be changed to 4/6, which means the 1st bounce would reach a height of 4m. Now, we need to find 2 thirds of 4, which is mildly harder. In order to find the exact value, we need to find what to multiply 3 by to get to 4. Unfortunately, you cant do that. Fortunately, though, I looked it up. So, On the 2nd bounce, the ball would reach 2.6 m. Now, we need to find 2 thirds of THAT, too, which would equal, on the third bounce, 1.7342 m.
The height of the ball after the third bounce is approximately 1.78 m.
To find the height after the third bounce, we need to calculate the height after each bounce and then determine the height after the third bounce.
Given that the ball rises to 2/3 of its previous height after each bounce, we can start with the initial height of 6 m and calculate the height after the first bounce, which is 6 * 2/3 = 4 m.
Similarly, after the second bounce, the height will be 4 * 2/3 = 8/3 m. Finally, after the third bounce, the height will be (8/3) * (2/3) = 16/9 m, which is approximately 1.78 m. Therefore, after the third bounce, the ball will reach a height of approximately 1.78 m.
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A graph of a parabola with x intercepts of negative 0.5, 0 and 2, 0 and a vertex of 0.5, 4 is shown.
Which function has a larger maximum? Type your answer as 1 or 2.
Answer:
The function 2 has a larger maximum.
Step-by-step explanation:
The vertex form of the parabola is
.... (1)
Where, (h,k) is the vertex.
The given functions are
..... (2)
Since the leading coefficient is negative, therefore it is a downward parabola. It means the vertex of the parabola is the maximum point.
On comparing (1) and (2), we get
Therefore the maximum value of the function is 2 at x=0.
The second function has x intercepts of (-0.5, 0) and (2, 0) and a vertex of (0.5, 4).
It is also a downward parabola because the parabola has two x-intercepts and the vertex lies above the x-axis.
Since the vertex is (0.5, 4), therefore the maximum value of the function is 4 at x=0.5.
Therefore function 2 has a larger maximum.
Answer:
the anwser is 2 guys. i got it correct
A. 64⁄27
B. 3⁄4
C. 27⁄64
D. 4⁄3
Answer:
Option D
Step-by-step explanation:
we know that
The product of two fractions is equal to the product of the numerators divided by the product of the denominators
so