Suppose that state’s record hightemperature of  102 



















 was
set in 1930, and the record low of 


 -14was
set in 1966. What is the range of these temperature extremes?

Answers

Answer 1
Answer: 102 minus -14 = the range of 116 degrees.
Answer 2
Answer: The range in temps true extremes is 116

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Which of the following shows the correct factorization of x3 - 5x2 - 14x?A. x(x + 7)(x + 2)B. x(x - 7)(x - 2)C. x(x + 7)(x - 2)D. x(x - 7)(x + 2)
8/20 in simplest form
If 4x+3=9x-4 then x =
Identify the domain and range of each function.y = 3 • 5xThe domain of this function is ?negative infinity to zero0 to infinitynegative infinity to infinityThe range of this function is?0 to infinity 3 to infinitynegative infinity to infinity

Find the zeros of the function h(x)=x^2-5x-50 by factoring

Answers

h(x)=x^2-5x-50=x^2-5x-25-25=x^2-25-5x-25\n\n=(x^2-25)-(5x+25)=(x^2-5^2)-5(x+5)\n\n=(x-5)\underline{(x+5)}-5\underline{(x+5)}=(x+5)(x-5-5)=(x+5)(x-10)\n\nAnswer:Zeros\ are\ x=-5\ and\ x=10.

What is the answer to this problem
8x-2=-9+7×

Answers

8x−2=−9+7x

Simplify:

8x−2=−9+7x

8x+−2=−9+7x

8x−2=7x−9

Subtract 7x from both sides.

8x−2−7x=7x−9−7x

x−2=−9

 Add 2 to both sides.

x−2+2=−9+2

x=−7

you want like terms on the same side. so you want x on the same side
subtract 7x from 8 x = x
add 2-9 = -7
now you have x= -7

a salesperson earns 350 a wee plus 10% of their weekly sales. Find the sales necessary for the salesperson to earn at least 800 in one week

Answers

If you would like to find the sales necessary for the salesperson to earn at least 800 in one week, you can calculate this using the following steps:

s ... weekly sales
350 + 10% of sales >= 800
350 + 10% of s >= 800
350 + 10% * s >= 800
10/100 * s >= 800 - 350
1/10 * s >= 450       /*10
s >= 450 * 10
s >= 4500

The correct result would be: weekly sales >= 4500.
350 + 10 \ percent \ of sales \ \textgreater \ = 800 

350 + 10 \ percent \ of sales \ \textgreater \ = 800

350 + 10 \ percent \ * sales \ \textgreater \ = 800

10/100 * sales \ \textgreater \ = 800 - 350

1/10 * sales \ \textgreater \ = 450 /*10

sales \ \textgreater \ = 450 * 10

sales \ \textgreater \ = 4500

BD bisects ABC, m/ABC =8x, m/ABD=2x + 30. Find m/DBC.

Answers

Answer:

Step-by-step explanation:

To find the measure of angle DBC, we can use the angle bisector theorem, which states that in a triangle, if a line bisects one of the angles, it divides the opposite side into segments proportional to the other two sides. In this case, BD bisects angle ABC, so:m∠ABD / m∠DBC = AB / BCWe are given:

m∠ABC = 8x

m∠ABD = 2x + 30So, we have:(2x + 30) / m∠DBC = AB / BCNow, we need to express AB / BC in terms of x. To do that, we'll use the fact that angles in a triangle add up to 180 degrees:m∠ABC + m∠ABD + m∠DBC = 180Substitute the given angle measures:8x + (2x + 30) + m∠DBC = 180Combine like terms:10x + 30 + m∠DBC = 180Now, isolate m∠DBC:m∠DBC = 180 - 10x - 30

m∠DBC = 150 - 10xNow, we can substitute this expression for m∠DBC back into our proportion:(2x + 30) / (150 - 10x) = AB / BCNow, you can solve for m∠DBC:Cross-multiply:(2x + 30)(BC) = (150 - 10x)(AB)Now, you would need more information about the relationship between AB and BC or additional angle measures to solve for the exact value of m∠DBC. Without that additional information, you can't determine the specific angle measure.

Which of the solution sets is all real numbers?
|x| < -1
|x| = -1
|x| > -1

Answers

Answer:

The solution sets is all real numbers in case of:

                        |x| > -1

Step-by-step explanation:

We know that modulus is a function with the property such that:

                      if a<0 then |a|= -a

that is the modulus of a negative number is positive and if a≥0

                                then |a| =a

and modulus of a positive value is also positive.

i.e. modulus function always gives positive value.

Hence,

1)

|x|<-1

This is not possible as modulus function always gives a value ≥0 for all real numbers.

2)

|x|= -1

This is also not possible as modulus of any number can't be negative.

3)

|x| > -1

The modulus of any number will definitely be greater than or equal to zero.

    Hence, the solution set contain all the real numbers.

The last one is all real number

Choose the equation that could be used to find three consecutive integers whose sum is 36.n + (n + 2) + (n + 4) = 36

n + (n + 1) + (n + 3) = 36

n + (n + 1) + (n + 2) = 36

n + (n − 1) + (n − 3) = 36

Answers

Let

n--------> the first integer

n+1------> the second consecutive integer

n+2-----> the third consecutive integer

we know that

n+(n+1)+(n+2)=36\n3n+3=36\n3n=36-3\n3n=33\nn=33/3\nn=11

the numbers are

11,12,13

therefore

the answer is

The equation is n+(n+1)+(n+2)=36

n +(n+1) + ( n+2)=36
the third answer