Cos theta = -5/6
180° <0<270°

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Answer 1
Answer:

Answer:choccy milk  solve all  yo problems

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Cuantas caras , aristas y vertices tiene un cono

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Un cono tiene 1 vértice y 0 aristas.

PLSSSSS HELP IF YOU TRULY KNOW THISSSSS

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Answer:

1

Step-by-step explanation:

Anything raised to 0 is 1

What is 45% of 40 in part, whole, and percent?

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The answer is eighteen.

In 1990 retail sales at bookstores were about $7.4 billion. In 1997 retail sales at bookstores were about $11.8 billion. Write a linear model for retail sales s (in billions of dollars) at bookstores from 1990 through 1997. Let T represent the number of year since 1990. Then estimate the retail sales at bookstores in 2012.

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hopefully this helps you and gives you insight in how to solve the problems from now on (:

= $11.8 + (2012-1997)([$11.8-$7.4][1997-1990])

= $11.8 + 5 ($4.4/7)

= $11.8 4/5 + $22/7

= $59/5 + $22/7

= $413/35 + $110/35

= $523/35 or $14 33/35

answer : SALES IN 2012 WOULD BE $14 33/35 BILLION OR $14.9 3/7

Final answer:

A linear model representing retail sales at bookstores from 1990 through 1997 is s(T) = 0.63T + 7.4. The estimated sales at bookstores in 2012 would be approximately $21.46 billion.

Explanation:

To solve this problem, we need to create a linear model. A linear model is a mathematical representation expressed as y = mx + b, where m is the slope, and b is the y-intercept.

To determine the slope (m), we subtract the ending value of retail sales from the starting value and divide by the number of years. So, subtract $7.4 billion (sales in 1990) from $11.8 billion (sales in 1997) and divide by 7 (the number of years from 1990 to 1997): (11.8 - 7.4) / 7 = 0.63. So, m = 0.63.

The y-intercept (b) is the value of y when x = 0. In this model, this corresponds to the sales in 1990, because x is the number of years since 1990, and 'x = 0' therefore corresponds to the year 1990. So, b = $7.4 billion.

The final linear model for retail sales at bookstores from 1990 through 1997 is s(T) = 0.63T + 7.4.

To estimate the retail sales at bookstores in 2012, we plug T = 22 (because 2012 is 22 years after 1990) into our linear model: s(22) = 0.63*22 + 7.4$21.46 billion. So, the estimated retail sales in bookstores in 2012 were about $21.46 billion.

Learn more about Linear Models here:

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What two numbers multiply to 44 and add up to 12?

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This pattern of question is always coming up. Since we can't easily guess, then let us set up simultaneous equation for the statements.

let the two numbers be x and y.

Multiply to 44.      x*y = 44 ..........(a)

Add up to 12.      x + y = 12 .........(b)

From (b)

y = 12 - x .......(c)

Substitute (c) into (a)

x*y = 44

x*(12 - x) = 44   

12x - x² = 44

-x² + 12x = 44

-x² + 12x - 44 = 0.       

Multiply both sides by -1

-1(-x² + 12x - 44) = -1*0

x² - 12x + 44 = 0.   

This does not look factorizable, so let us just use quadratic formula

comparing to ax² + bx + c = 0, x² - 12x + 44 = 0,  a = 1, b = -12, c = 44 

x = (-b + √(b² - 4ac)) /2a   or (-b - √(b² - 4ac)) /2a


x = (-(-12) + √((-12)² - 4*1*44) )/ (2*1)    

x = (12 + √(144 - 176) )/ 2

x = (12 + √-32 )/ 2

√-32 = √(-1 *32) = √-1 * √32 = i * √(16 *2) = i*√16 *√2 = i*4*√2 = 4i√2

Where i is a complex number.  Note the equation has two values. We shall include the second, that has negative sign before the square root.

x = (12 + √-32 )/ 2      or     (12 - √-32 )/ 2   

x = (12 + 4i√2 )/ 2              (12 - 4i√2 )/ 2 

x = 12/2 + (4i√2)/2                12/2 - (4i√2)/2

x = 6 + 2i√2            or         6 - 2i√2

Recall equation (c):

y = 12 - x, When x = 6 + 2i√2,  y = 12 - (6 + 2i√2) = 12 - 6 - 2i√2 = 6 - 2i√2

When x = 6 - 2i√2,  y = 12 - (6 - 2i√2) = 12 - 6 + 2i√2 = 6 + 2i√2


x = 6 + 2i√2,  y = 6 - 2i√2

x = 6 - 2i√2,  y = 6 + 2i√2

Therefore the two numbers that multiply to 44 and add up to 12 are:

6 + 2i√2 and 6 - 2i√2
xy=44\n x+y=12\n\n xy=44\n x=12-y\n\n (12-y)y=44\n 12y-y^2=44\n y^2-12y+44=0\n y^2-12y+36+8=0\n (y-6)^2=-8

No solutions in real numbers.

In complex numbers:
(y-6)^2=-8\n y-6=-√(-8) \vee y-6=√(-8)\n y=6-2\sqrt2 i \vee y=6+2\sqrt2 i\n\n x=12-(6-2\sqrt2i) \vee x=12-(6+2\sqrt2i)\n x=12-6+2\sqrt2i \vee x=12-6-2\sqrt2i\n x=6+2\sqrt2i \vee x=6-2\sqrt2i

These numbers are 6-2\sqrt2i and 6+2\sqrt2i.

2x+5y=34, x+2y=14
solve the system of linear equations

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x=2 and y=6   i hope this helps