Answer:
Probability: (About) 0.8
Step-by-step explanation:
~ Provided that point X is randomly plotted on the line segment JM, we must calulculate the probability with which it lands on KM the first time ( implied ) ~
1. We know that the line segment JM, by the Partition Postulate ⇒ JK + KL + LM. With that being said JM = 3 + 7 + 4 = 14 units
2. Now line segment KM, by the Partition Postulate ⇒ KL + LM. With the assigned values, we can tell that KM = 7 + 4 = 11 units
3. If we were to determine the porbability that X lands on the line segment KM, considering the first try it would be KM/JM ⇒ Probability: 11/14
Please show all work
Answer:
Step-by-step explanation:
t = Time taken
u = Initial velocity
v = Final velocity
s = Displacement
a = Acceleration due to gravity = 32 ft/s²
Here, u = 0 so,
The equation is
Time taken by the ball to hit the ground is 1.22 seconds
Answer:
The coefficient ( ) of 5a is filled by and the coefficient ( ) of a² is filled by ' 0 '
Step-by-step explanation:
The given expression is 6a - ( )5a = ( )a² - 35a
To find the missing coefficient, compare the left and right side of expression,
First compare the 6a - ( )5a = - 35a
6a+35a = ( )5a
41a = ( )5a
divide both the sides by 5a,
The coefficient ( ) of 5a is filled by
Now, compare 0 = ( )a²
So, the coefficient ( ) of a² is filled by ' 0 '
Hence, The coefficient ( ) of 5a is filled by and the coefficient ( ) of a² is filled by ' 0 '
-16 t+3.5
Answer:
on the x axis start from the point and draw it forward to -16(basically negative side) the draw a line upwards on the y-axis to the line inbetween 3 and 4 (this is on the y axis)
Step-by-step explanation: