Write an algebraic expression for two fifths of the square of a number
Answers
The algebraic expression for two-fifths of the square of a number will be (2/5)x².
What is Algebra?
The analysis of mathematical representations is algebra, and the handling of those symbols is logic.
The square of the number means the number is multiplied by itself.
The algebraic expression for two-fifths of the square of a number will be
Let the number be x.
Then the square of the number will be
⇒ x²
And the two-fifth number is expressed as,
⇒ 2/5
The algebraic expression for two-fifths of the square of a number will be
⇒ (2/5)x²
Thus, the algebraic expression for two-fifths of the square of a number will be (2/5)x².
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(2/5)x^2
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Answers
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Your answer is 28 - 4x.
Answers
Answers
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Answers
198 + (199*3) + (200*2) +(201*5) + (202*2) = 2604
frequency = 1 + 3 +2 + 5 + 2 = 13
201 = (2604 + x )/14
multiply both sides by 14
x = 201*14 = 2604 +x
x = 2814 = 2604 +x
subtract 2604 from both sides:
x = 2814 - 2604
x = 210 cm
height of new player = 210 cm
Answers
Answer:
4.5 per package
Step-by-step explanation:
Though they give us 4 different pairs of values on the table, we only need 1 pair to solve this question. For simplicity, lets chose the pair of whole numbers:
54 : 12
This is the ration of servings to packages, or the servings per package.
To get our answer, we must find how many servings per 1 package, so we need to divide by 12:
=
4.5 : 1
This means that there are 4.5 servings per 1 package!
Hope this helps!
Answers
The slope-intercept form of a line is y = mx + b, where m is the slope.
Given line: 2y - 3x = 6
To convert it into slope-intercept form, isolate y:
2y = 3x + 6
y = (3/2)x + 3
The slope of the given line is (3/2).
Now, let's find the slopes of the lines AB, BC, and CA:
1. Line AB:
Coordinates of A(-5, -12) and B(11, -4)
Slope (m) of AB = (change in y) / (change in x) = (-4 - (-12)) / (11 - (-5)) = 8 / 16 = 1/2
2. Line BC:
Coordinates of B(11, -4) and C(7, 6)
Slope (m) of BC = (change in y) / (change in x) = (6 - (-4)) / (7 - 11) = 10 / (-4) = -5/2
3. Line CA:
Coordinates of C(7, 6) and A(-5, -12)
Slope (m) of CA = (change in y) / (change in x) = (-12 - 6) / (-5 - 7) = -18 / (-12) = 3/2
Now, let's compare the slopes:
- Slope of the given line: 3/2
- Slope of AB: 1/2
- Slope of BC: -5/2
- Slope of CA: 3/2
The line that is parallel to the given line 2y - 3x = 6 is Line CA, as it has the same slope of 3/2.
Answer:
CA.
Step-by-step explanation:
To find the gradient (slope) of the line 2y - 3x = 6, we need to rewrite the equation in slope-intercept form (y = mx + b), where "m" represents the gradient. Here's how:
2y - 3x = 6
First, isolate "y" on one side of the equation:
2y = 3x + 6
Next, divide both sides by 2 to solve for "y":
y = (3/2)x + 3
Now we can see that the gradient (slope) of the line is (3/2).
Now, let's analyze the three lines AB, BC, and CA, formed by the points A(-5, -12), B(11, -4), and C(7, 6).
The gradient (slope) of the line AB can be calculated using the coordinates of points A and B:
Gradient of AB = (Change in y) / (Change in x) = (-4 - (-12)) / (11 - (-5)) = 8 / 16 = 1/2
The gradient (slope) of the line BC can be calculated using the coordinates of points B and C:
Gradient of BC = (Change in y) / (Change in x) = (6 - (-4)) / (7 - 11) = 10 / (-4) = -5/2
The gradient (slope) of the line CA can be calculated using the coordinates of points C and A:
Gradient of CA = (Change in y) / (Change in x) = (-12 - 6) / (-5 - 7) = -18 / (-12) = 3/2
Now, we compare the gradients of the lines AB, BC, and CA to the gradient of the line 2y - 3x = 6 (which is 3/2). We see that the line CA has the same gradient (3/2) as the line 2y - 3x = 6.
So, the line CA is parallel to the line 2y - 3x = 6.