Answer: The volume of stock HCl solution required to make laboratory solution will be 0.25L
Explanation:
To calculate the volume of stock solution required to make the laboratory solution, we use the equation:
where,
are the molarity and volume of stock solution.
are the molarity and volume of laboratory solution.
We are given:
Putting values in above equation, we get:
Hence, the volume of stock HCl solution required to make laboratory solution will be 0.25L
Answer:
0.85 mol/L.
Explanation:
M = (no. of moles of solute)/(Volume of the solution (L))
no. of moles of calcium phosphate = 2.125 mol.
Volume of the solution = 2.5 L.
∴ M of calcium phosphate = (2.125 mol)/(2.5 L) = 0.85 mol/L.
Answer:
A
An acid and a base
Explanation:
c. a change in temperature
d. a change in density
e. a change in structure
Percentage % yield = 91.8%
Given:
20 g NaCl
45 g AgCl
To find:
% yield=?
The balanced chemical equation will be:
NaCl + AgNO₃ ⇒ AgCl + NaNO₃
First, we need to calculate moles of NaCl.
Then, calculate moles of AgCl from equation:
Mass AgCl(theoretical) :
Now, calculate for percentage yield.
The percentage yield will be 91.8%.
Learn more:
%yield = 91.8
Given
20 g NaCl
45 g AgCl
Required
%yield
Solution
Reaction
NaCl + AgNO₃ ⇒ AgCl + NaNO₃
mol NaCl :
= mass : MW
= 20 g : 58,44 g/mol
= 0.342
mol AgCl from equation :
= 1/1 x mol NaCl
= 1/1 x 0.342
= 0.342
Mass AgCl(theoretical) :
= mol x MW
= 0.342 x 143,32 g/mol
= 49.02 g
%yield = (actual/theoretical) x 100%
%yield = (45/49.02) x 100%
%yield = 91.8
gasoline
carbon
glucose
Answer: The correct answer is carbon.
Explanation:
Combustion reaction is defined as the reaction in which a hydrocarbon burns in oxygen or reacts with oxygen gas to produce carbon dioxide and water molecule.
Fossil fuels are defined as the hydrocarbons which mainly contains coal, fuel oil, natural gas etc..
When fossil fuels are burned in air, it mainly releases carbon dioxide, sulfur dioxide, methane, nitrous oxide etc..
The major component released during the combustion of fossil fuels is carbon.
Hence, the correct answer is carbon.