MATHEMATICS MIDDLE SCHOOL

If ur teacher tells you to do questions 6 through 19 in your math book for homework, how many question is that?

Answers

Answer 1
Answer:

Answer:

13 questions :3

Step-by-step explanation:
Answer 2
Answer:

Answer:13


Step-by-step explanation:

simple math

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If fir trees: yew trees is 3:4 there are 18 fir trees how many yew trees

Answers

Here are the given ratio based on the problem: => Fir trees : yew trees = 3 : 4 , there Fir trees is equivalent to 3 and yew trees is 4.Now, given that the value of Fir trees is 18, based on the ratio, how many yew trees will there be? => 3 : 4 = 18 : x, where x is the unknown value of yew trees. To solve, first let's multiply the inner value of the given proportion. => 4 * 18 = 72Then, divide 72 with the outer value => 72 / 3 = 24.Therefore, the ratio now is 18 : 24

3. Find a solution to the following system of equations.
-3x + 3y = -9
-3x + y = 7

Answers

Answer:

x = 5

y = 2

Step-by-step explanation:

-3x + 3y = -9

3y = 3x - 9

Equation 1. y = x - 3

-3x + y = 7

Equation 2. y = 3x + 7

So, put number 1 equation to number 2's y :

x - 3 = 3x + 7

x -3x = 7 + 3

-2x = 10

2x = 10

x = 10/2

x = 5

And, put x, which is 5 , to the any equation to figure out the y.

This time, I'll use equation number 1.

y = 5 - 3

y = 2

What property describes the number sentence 6+0=6?

Answers

commutative property

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Answers

Answer:

Yep. I can help you.

Step-by-step explanation:

What are the roots of the equation x^2+6x-9=0

Answers

Answer:

The roots of the quadratic equation are

x=-3+3√(2)

x=-3-3√(2)

Step-by-step explanation:

we have

x^(2) +6x-9=0

we know that

The formula to solve a quadratic equation of the form ax^(2) +bx+c=0 is equal to

x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}

in this problem we have

x^(2) +6x-9=0

so

a=1\nb=6\nc=-9

substitute in the formula

x=\frac{-6(+/-)\sqrt{6^(2)-4(1)(-9)}} {2(1)}

x=\frac{-6(+/-)√(72)} {2}

x=\frac{-6(+/-)6√(2)} {2}

x=-3(+/-)3√(2)

x=-3(+)3√(2)

x=-3(-)3√(2)

Given equation is :

x^(2)+6x-9=0

We will solve this quadratic equation, using the formula:

x1,2=\frac{-b+\sqrt{b^(2)-4ac}}{2a} and

x1,2=\frac{-b-\sqrt{b^(2)-4ac}}{2a}

Now, putting a=1 , b=6 and c =-9 we get

x=\frac{-6+\sqrt{6^(2)-4*1(-9)}}{2*1} and

x=\frac{-6-\sqrt{6^(2)-4*1(-9)}}{2*1}

Final solutions are:  x=3(√(2)-1) and

x=-3(√(2)+1)

The English class has half as many students as the math class

Answers

If you are looking for an equation to solve it, it is E=m/2

Answer:

The english class would have half as more so divide the amount that the math class has by 2 and then add i to the english class

Step-by-step explanation:
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