The equation of the line perpendicular to the given line will be =
y = x + 17
We have a general equation of line as - 2x - 3y = 12 which passes through the point (16, -7).
We have to determine the general equation of the line perpendicular to this line.
The general equation of a straight line is as follows -
y = mx + c
where -
m - slope of line
c - intercept of line on y - axis.
According to question, we have -
Equation of Line = 2x - 3y = 12
Rearranging the above equation of line, we get -
3y = 2x - 12
y =
Therefore, the slope of this line will be = 2/3
Two lines which are perpendicular to each other have the following relation among their slopes =
m(1) x m(2) = -1
Therefore, the slope of line perpendicular to the given line will be -
m(2) = -3/2
Now, assume that the equation of line perpendicular to the given line be-
y = mx + c
y = x + c
Since, this line passes through the point (16, -7), therefore-
- 7 = + c
-7 + 24 = c
c = 17
Hence, the equation of the line perpendicular to the given line will be =
y = x + 17
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8 units
13 units
14 units
The solution is, the length of line segment VT is 13 units.
A straight line is an endless one-dimensional figure that has no width. It is a combination of endless points joined both sides of a point and has no curve.
Here, given that, point P is between V and T,
Then, V&T are the endpoints & P is on the line.
V---------------------P--------------------T
So, we get, VP+PT=VT
from the given figure we get,
The solution is, the length of line segment VT is 13 units.
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Answer:
C. 13
Step-by-step explanation:
Domain of - 5 : x ≥ 25 .
Range of √x - 5 : y ≥ -5 .
Given,
f(x) = √x - 5
Here,
To find the domain,
√x - 5 ≥ 0
√x ≥ 5
Squaring both sides ,
x ≥ 25 .
Thus domain of √x - 5 is x ≥ 25 .
Range of √x - 5,
To define the range of the function the value of x can not be negative as it will make the function complex .
So,
Range will be ,
y ≥ -5 .
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The ratios of consecutive y-values are equal for evenly spaced x-values.
The change in y-values is not constant, but the change is constant for evenly spaced x-values.
The change in y-values is constant for evenly spaced x-values.
The change in x values and y values are proportional to each other for the given case. The correct option is (D).
The slope of a straight line is the tangent of the angle formed by it with the positive x axis as the reference.
The negative slope indicates the rate of decrease while the positive shows the rate of increase.
In order to form a linear equation from a table,
The slope has to be found first.
For this, the ratio of the difference in the values of x and y are taken.
Which implies that the change in x values are directly proportional to the change in the values of y.
And the proportionality constant is known as the slope.
=> (y₂ - y₁) ∝ (x₂ - x₁)
=> (y₂ - y₁)/(x₂ - x₁) = m
Hence, the change in y values are constant for change in x values.
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ANSWER:
the answer is D.
X+y=-3
X-y=13