In the circle, measure of Arc BC = 62°. The diagram isn't drawn to scale. what is the measure of Arc BCP?

Answers

Answer 1

Answer:

Answer:

Option D. ∠BCP = 31°

Step-by-step explanation:

As we know by the theorem tangent and chords, an angle formed by a chord and a tangent that intersect on a circle is half the measure of the intercepted arc.

Theorem clearly reveals ∠BCP = $(mBP)/(2)$

Since arc BC = 62°

So ∠BCP = $(62)/(2)=31$

Option D. ∠ BCP = 31° is the answer.

Answer 2

Answer: PQ is the tangent, therefore you can use a theorem: The arc measure is double the amount of the angle the tangent makes.

So: 62/2=31

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Trina earns 38.50 tutoring for three hours. Write an equation relating her earnings M to the number of hours H she tutors. How much will Trina earn tutoring for three hours?

Answers

Answer: M = 12.83 * H

Step-by-step explanation:

38.50 for 3 hours.

Calculate hourly wage by dividing both sides by 3

$12.83333333333333 per hour. let's round this to $12.83

So M = hourly wage * H = M = 12.83 * H

Find the value of x
a) 5
b) -1
c) 6
d) 2

Answers

Answer:

a) 5

Step-by-step explanation:

x+2 = 2x-3

-x -x

2 = x-3

+3 +3

5 = x

I think i had thw correct answers for thr last two but the keep coming up as incorrect

Answers

Answer:

B. 40

C. 8

Step-by-step explanation:

5t-2r=25

solve for t.

Answers

Given 5t - 2r = 25

To solve for t,
first, we add 2r to both sides of the equation, to get

5t - 2r + 2r = 25 + 2r

5t = 25 + 2r

Next, we divide both sides of the equation by 5, to get

$t= (25+2r)/(5)$

Answer:

t= \frac{25+2r}{5}

Step-by-step explanation:

Which of the following polygons can form a regular tessellation?A. Regular heptagon
B. Regular pentagon
C. Regular octagon
D. Square

Answers

Answer:

D. Square

Step-by-step explanation:

A square is a regular tessellation because a regular tessellation is a pattern made up of only one single shape placed in some kind of pattern.

Zx5+3 please help me

Answers

Answer: 5z + 3

-Use P.E.M.D.A.S
(Parentheses, Exponents, Multiply or divide, Add or subtract)

-Multiply z times 5 first
z x 5 = 5z

-Then add 5z to 3
5z + 3

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