The volume of the box as a function of x V(x) = x ( 60 -2x )( 15-2x )
The volume of the box as a function of x inches 0.55 inches ≤ x ≤ 6.79
The volume of the box is maximum x ≥ 6.79 inches
Given ,
The box with no top that is to be made by removing squares of width x
The corners of a 15-in by 60-in piece of cardboard.
V(x) = x ( 60 -2x )( 15-2x )
Where : x = height , ( 60 - 2x ) = length , ( 15 -2x ) = width
The volume of the box as a function of x is V(x) = x ( 60 -2x )( 15-2x )
The volume of the box ≥ 450 inches
V(x) = x ( 60 -2x )( 15-2x )
The volume of the box is at least 450 cubic inches.0.55 inches ≤ x ≤ 6.79 inches
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Answer:
a) V(x) = x ( 60 -2x )( 15-2x )
b) 0.55 inches ≤ x ≤ 6.79 inches
c) x ≥ 6.79 inches
Step-by-step explanation:
Given data:
No top, cardboard dimensions ; 15-in by 60-in
a) A function for the volume of the box as a function of x the Volume can be represented by this function below
= V(x) = x ( 60 -2x )( 15-2x )
where : x = height , ( 60 - 2x ) = length , ( 15 -2x ) = width
b) determine x so that the volume of the box ≥ 450 inches
450 = x( 60 - 2x ) ( 15 -2x ) ( solving the equation )
0.55 inches ≤ x ≤ 6.79 inches
c ) The value of x for which volume of the box is maximum
will be x ≥ 6.79 inches
b. x can only equal 7.4.
c. x can equal –3.2 or –7.4.
d. x can equal –3.2 or 7.4.
we have
Step 1
Find the first solution (case positive)
Eliminate the parenthesis left side
Subtract both sides
Divide by both sides
Step 2
Find the second solution (case negative)
Eliminate the parenthesis left side
Adds both sides
Divide by both sides
therefore
the answer is the option C
x can equal –3.2 or –7.4
18x2 + 78xy − 24y2
−18x2 − 78xy + 24y2
−18x2 + 72xy − 24y2
Answer:
The answer is A I just took the test
Step-by-step explanation:
Answer:
=439.04 ft^2
Step-by-step explanation:
First find the area of the total rectangle
A = l*w
40*16 =640 ft^2
We have 2 semi circles with diameter 16
That equals 1 circle with diameter 16
The radius is d/2 = 16/2 =8
The area of a circle is
A = pi r^2
A = (3.14) (8)^2
=200.96
Subtract the unshaded area from the total area
640-200.96=439.04
a. 2
b. 5
c. 20
d. 10