The dark absorption lines of an atom's spectrum correspond to the same energies as the bright emission lines. They both reflect energy changes in electron states.
The dark lines of an atom's absorption spectrum are at the same energies as the bright lines of its emission spectrum, therefore the correct answer is a. The bright lines are at the same energies as the dark lines. Absorption spectra are produced when electrons absorb energy and move to a higher energy level, while emission spectra are observed when electrons lose energy and return to a lower energy level.
The dark lines (absorption) and bright lines (emission) coincide because the energy required to move an electron from a lower to higher energy level matches the energy released when an electron drops from a higher to lower state.
#SPJ12
Answer:14-6= 8
Explanation:
ATOMIC NUMBER = 6 = NO. OF PROTON
MASS NO .= NO. OF PROTONS + NO. OF NEUTRONS
14=6+NEUTRONS
14-6=NEUTRONS
8=NEUTRONS
The correct answer to the question is : 9375 N.
CALCULATION:
As per the question, the mass of the car m = 1500 Kg.
The diametre of the circular track D = 200 m.
Hence, the radius of the circular path R =
=
= 100 m.
The velocity of the truck v = 25 m/s.
When a body moves in a circular path, the body needs a centripetal force which helps the body stick to the orbit. It acts along the radius and towards the centre.
Hence, the force acting on the car is centripetal force.
The magnitude of the centripetal force is calculated as -
Force F =
=
= 9375 N. [ANS}
The centripetal force is provided to the car in two ways. It is the friction which provides the necessary centripetal force. Sometimes friction is not sufficient. At that time, the road is banked to some extent which provides the necessary centripetal force.
The magnitude of the net force on the car is 9375 N, directed towards the center of the track. The net force is caused by the combination of the car's weight and the normal force of the road. These forces provide the necessary centripetal force to keep the car in its circular path.
The magnitude of the net force on the car can be calculated using the formula F = m×a, where m is the mass of the car and a is its acceleration. Since the car is moving in a circular path, its acceleration can be determined using the formula a = v^2/r, where v is the velocity of the car and r is the radius of the circular track. The direction of the net force is towards the center of the circular track, as it provides the necessary centripetal force to keep the car moving in a circular path.
Using the given values, the magnitude of the net force on the car is F = (1500 kg) × (25 m/s)^2 / (100 m) = 9375 N. The direction of the net force is towards the center of the circular track since it provides the centripetal force required to keep the car in its circular path.
The net force on the car is caused by two external forces: the weight of the car and the normal force of the road. The weight of the car acts vertically downwards, while the normal force of the road acts perpendicular to the surface. These two forces combine to provide the net force that keeps the car moving in a circular path.
#SPJ3
the solvent fully dissolves in the solute
the solvent is always water
the solute fully dissolves in the solvent
Answer:
The solute fully dissolves in the solvent
Explanation:
This is because for a solution to be called a homogeneous mixture, all the solute must be dissolved in the solvent, without the particles of the solute being visible in the solvent.