Answer : The correct option is, 318.1 J
Solution :
The given chemical reaction will be,
In this reaction, X and Y are the reactants and W and Z are the products.
As we know that the energy remains conserved during the chemical reaction.
So,
Sum of energy of product = Sum of energy of reactant
Therefore, the amount of chemical energy of product Z contain will be, 318.1 J
Answer:
318.1 J
Explanation:
The reaction given is:
X + Y → W + Z
The chemical energy of the reaction (ΔU), is the variation of the chemical energy, so is the chemical energy of the products (UW and UZ) less the chemical energy of the reactants (UX and UY).
If the reaction loses the chemical energy, it must be negative, and the chemical energy that a substance contains, is positive.
ΔU = (UW + UZ) - (UX + UY)
-111.6 = (41.9 + UZ) - (199.3 +272.3)
-111.6 = 41.9 + UZ - 471.6
- UZ = - 429.27 + 111.6
-UZ = - 318.1
UZ = 318.1 J
Answer:
20322
Explanation:
Answer:
Chemical properties can be tested without changing the substance
Explanation:
Copper (II)iodide
Tin(IV) nitride
Choro minim (II)bromide
Iron(III)phosphide
Compounds are classified as binary or ternary based on the number of elements present in the compound. The chemical formulas for the given compounds include nickel(III)oxide, copper(II)iodide, tin(IV)nitride, chloro minimium(II)bromide, and iron(III)phosphide.
In order to identify whether a compound is binary or ternary, we need to analyze its chemical formula. Binary compounds consist of two elements, while ternary compounds consist of three or more elements. The chemical formula for each compound is as follows:
#SPJ2
Answer:
there are 18.65 grams of sodium nitrate dissolved in 126 grams of the solution that is 14.8% by mass of the compound.
Explanation:
To find the mass of sodium nitrate dissolved in the solution, we can use the concept of percent composition.
First, we need to determine the mass of the solution that is made up of sodium nitrate. Since the solution is 14.8% by mass of the compound, we can calculate this by multiplying the total mass of the solution by the percentage:
Mass of sodium nitrate in solution = (14.8/100) * 126 g
Mass of sodium nitrate in solution = 18.65 g
Therefore, there are 18.65 grams of sodium nitrate dissolved in 126 grams of the solution that is 14.8% by mass of the compound.