One route along flat terrain from Hermansville to Melville is to drive straight north from Hermansville for 120 miles to Jamestown, then, at Jamestown, to drive straight west for 80 miles to Melville. If a straight,flat road existed between Hermansville and Melville,approximately how many miles long would it be?
Answers
Answer 1
Answer:
approx. 144 mileswe can find this length by use of pythagorean's threorom. we use it because there's a 90 degree angle in the triangle, first we go due north, then turn due west.
+ = , where a & b and the lines attached to the right angle, and c is the hypotenuse, also the length we're looking for.
+ = 14400 + 6400 = 20800 = c = ≈ 144.2
Answer 2
Answer:
Approximately 144 miles. You have to use the pythagorean theorem. a^2+b^2=c^2. 120 and 80 will be the legs, a and b. 120^2 + 80^2 = c^2. 14400 + 6400 = 20800. Remember, c is squared, so to find the answer, you need to find the square root of 20800, which is 144.222051019. Therefore, c, the road between Hermansville and Melville, would be approximately 144 miles.
Match the following problems with their answer, HELP ME PLEASE!!!!!
Answers
Answer:
1. 12.5%
2. 26%
3. 51
4. 16
Step-by-step explanation:
3/24=0.125 -> 12.5%
65/250=0.26 -> 26%
300*0.17=51
0.4*40=16
If 3 waves happen in 6 seconds how many happen in 1 second? How do I solve this and what's the answer?
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you would do 3 divided by 6 and that would give you th answer and the answer is 0.5 so that would mean half a wave happens every second
If x + y = 9, z + y = 12, and z + x = 11, what is the average (arithmetic mean) of x, y and z?
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What is the value of the expression when a = 5 and b = 3? 4a^2 5b^3a. 55 b. 74 c. 81 d. 145
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Identify the solutions of the system of equations, if any x+5y=6 6x-10y=12
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so assuming x and y remain constant, we can make one of the place holders negative and add the equations together to cancel each other out so
we can cancel out the y terms since 5 is close to 10 (x+5y=6) times 2=2x+10y=12 add this to 6x-10y=12 2x+6x+10y-10y=12+12 8x=24 divide both sides by 8 x=3 subsitute into first equation x+5y=6 3+5y=6 5y=3 y=3/5 x=3
What is the product of 4n^+3=7n?
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so if you solve for n 4n^2+3=7n make into trinomial subtract 7n from both sides 4n^2-7n+3=0 if we can factor this, then we can asume that the factors are equal to zero becase if xy=0 then assume x and/or y=0 so
to factor an equation in ax^2+bx+c where a is greater than 1 then b=t+z a times c=t times z to factor 4n^2-7n+3 you do 4 times 3=12 what 2 numbers multiply to get 12 and add to get -7 the numbers are -3 and -4 so split up the -7 4n^2-4n-3n+3 group (4n^2-4n)+(-3n+3) undistribute (4n)(n-1)+(-3)(n-1) reverse distributive property ab+ac=a(b+c) (4n-3)(n-1)=0 set each to zero 4n-3=0 add 3 to both sides 4n=3 divide both sides by 4 n=3/4