Answer:
Depth of the water in the aquarium is 14 cm.
Step-by-step explanation:
Length and width of the aquarium is given as 18.5 cm and 15 cm
Amount of water in the aquarium = Volume of the rectangular prism
3885 = Length × Width × Height
3885 = 18.5×15×Height
3885 = 277.5 × h
h =
h = 14 cm
Therefore, Depth of the water in the aquarium is 14 cm.
Answer:
38.7°
Step-by-step explanation:
∆ = Tan-1(opposite/ Adjacent)
=Tan-1(8/10)
= 38.66°
= 38.7° to n nearest tenth
Answer:
The answer is 4.69 sec
Step-by-step explanation:
We know time taken = distance / speed
here 1 mile = 5280 feet , so 767 mph = 767x 5280 feet /( 60x60 ) s = 1124.93 feet / sec .
now , time taken
It will take 4.69 sec for the sound to travel 1 mile or 5280 feet .
beans are blue?
36b2 − 24b + 8
16x2 + 24x + 9
4a2 − 10a + 25
Answer: (c) .
Step-by-step explanation:
(a) cannot be further factorised, so this is not correct option.
(b) also cannot be expressed as factors, and hence this is too not correct.
(c) , the correct one.
(d) cannot be factorised, so its not correct.
Thus, (c) is the correct option.
Answer:
About 428 N
Step-by-step explanation:
Weight = 1,500 * 9.8 = 14,700 N
Density = Mass ÷ Volume
1,030 = 1,500 ÷ V
V = 1,500 ÷ 1,030 = 1.46 m^3.
Buoyant force = Density * g * V
Buoyant force = 1,000 * 9.8 * (1,500 ÷ 1,030)
Buoyant force = 9,800 * (1,500 ÷ 1,030) = 14,272 N.
Net force = 14,700 – [(9,800 * (1,500 ÷ 1,030)]
The upward normal force on a 1500 kg submerged hippo is approximately equal to its weight, calculated as its mass times the acceleration due to gravity (1500 kg × 9.81 m/s²), resulting in a force of 14715 N.
The question is asking about the upward normal force on a submerged hippo in a lake. To find this force, we must understand that the upward normal force that the ground (or in this case, the lake bed) exerts on the hippo is equal to the weight of the hippo, which is the product of the hippo's mass (m) and the acceleration due to gravity (g).
In equation form: Normal Force = m × g. Plugging in the values, we have a 1500 kg hippo and the acceleration due to gravity is approximately 9.81 m/s². Therefore, the upward normal force is:
Normal Force = 1500 kg × 9.81 m/s² = 14715 N.
This is the approximate value of the upward normal force exerted on the hippo standing on the bottom of the lake.
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