Help answer 1/5x-2/3y=30 when y = 15

Answers

Answer 1

Answer:

The value of the variable x at y = 15 will be 200.

What is the solution to the equation?

The distribution of weights to the variables involved that establishes the equilibrium in the calculation is referred to as a result.

The equation is given below.

(1/5)x - (2/3)y = 30

Solve the equation for x, then we have

(1/5)x = 30 + (2/3)y

x = 150 + (10/3) y

The value of the variable x at y = 15 will be

x = 150 + (10/3) × 15

x = 150 + 50

x = 200

The value of the variable x at y = 15 will be 200.

More about the solution of the equation link is given below.

brainly.com/question/545403

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Answer 2

Answer: $\frac{1}5x-\frac{2}3y=30$

Plug in 15 for y.

$\frac{1}5x-\frac{2}3(15)=30$

2/3 of 15 is 10.

$\frac{1}5x-10=30$

Add 10 to each side.

$\frac{1}5x=40$

Divide each side by 1/5.
(dividing by a fraction is the same as multiplying by its reciprocal...flip 1/5...×5)

$\boxed{x=200}$

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Answers

Answer:

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Answers

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