Optimization-Of all rectangles with a perimeter of 10, which one has the maximum area? (Give dimensions)

Answers

Answer 1
Answer: Do you want a proof or just the answer?
The answer is: the square (2.5x2.5).

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Mr young has 30 times as many pencils as jack. The whole class has 200 times as many pencils as jack. If jack has 2pencils, how many pencils does mr young have ? And the whole school have?

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well you would do 30*2= 60
and that would be your answer

Translate the sentence into an equation.Nine times the sum of a number and 3 is 5.
Use the variable x for the unknown number.

Answers

Answer: 9 (3 + x) = 5

Step-by-step explanation: hope this helps

Answer:

9(X) x 3 =5

Step-by-step explanation:

The Quinn family drove 228 miles in 4 hours at a constant rate. Which equation can be used to determine how far they traveled each hour?

A. d = 228/4


B. d = 228 x 4


C. d = 228 + 4


D. d = 228 - 4

Answers

A. The distance traveled each hour would be the total distance divided by the number of hours.
Distance = Time x Rate of travel miles/hr so D/T = rate of travel 228/4 = 57 miles/hr. Answer is A

116 is 145% of what number

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116\ \rightarrow\ 145\%\nx\ \rightarrow\ 100\%\n\nx= (116\cdot100\%)/(145\%) \n\nx= (4\cdot29\cdot5\cdot20)/(5\cdot29) \ \ \ \Rightarrow\ \ \ x=4\cdot20=80
116 = 145% x ?
116 = 1.45 x ?
116 ÷ 1.45 = 80
? = 80

Can you express 9/9 as a mixed number

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9/9 simply equals 1 there is no mixed number

(0)Radio direction finders are placed at points A and B, which are 4.32 mi apart on an east-west line, with A west of B. The transmitter has bearings 10.1 from A and 310.1 from B. Find the distance from A.

Answers

2.95 miles

The question involves radio direction finders placed at two points, A and B, which are 4.32 miles apart on an east-west line. The transmitter has bearings 10.1 degrees from A and 310.1 degrees from B. The task is to determine the distance from A.In order to determine the distance from A, the first step is to construct a diagram of the scenario to visualize the placement of the three points, A, B, and the transmitter. To do so, a coordinate system is used, with A being located at the origin (0,0).The bearing of the transmitter from A is 10.1 degrees, which can be plotted on the diagram as a straight line from the origin to an angle of 10.1 degrees to the east. Similarly, the bearing of the transmitter from B is 310.1 degrees, which can be plotted on the diagram as a straight line from point B to an angle of 49.9 degrees to the west.To determine the distance from A, the Law of Cosines can be applied, which states that c^2 = a^2 + b^2 − 2ab cos(C), where c is the unknown side, a and b are the known sides, and C is the angle opposite the unknown side. In this case, c is the distance from A, a is the distance from B, and b is the distance between A and B. The angle C is equal to the sum of the two bearings (10.1 + 49.9 = 60 degrees).Therefore, c^2 = a^2 + b^2 − 2ab cos(C) can be rewritten as:dA^2 = d^2 + 4.32^2 - 2d(4.32)cos(60)dA^2 = d^2 + 4.32^2 - 2d(4.32)(1/2)dA^2 = d^2 + 4.32^2 - 2.16dTo solve for dA, the equation can be rearranged and solved for d:0 = d^2 - 2.16d + dA^2 - 4.32^2d = 1.08 ± sqrt(1.08^2 - dA^2 + 4.32^2)The positive root of this equation can be used to determine dA:dA = 1.08 + sqrt(1.08^2 - d^2 + 4.32^2)dA = 1.08 + sqrt(1.08^2 - 4.32^2 cos^2(10.1))dA ≈ 2.95 milesTherefore, the distance from A is approximately 2.95 miles.

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