Really need help with number 3 please. Thanks. need help with all really quick but especially number3. Thanks again. God Bless!!!#1
–3y – 12 = –4
Need help with solving for Y.

#2
Compute a value for t that satisfies the equation below.
-2/3t - 2= -3

#3
A student attempts to solve for c in the equation below. Which statement best applies to the work shown below?

2c + 3 = 1

2c + 3 – 3 = 1 – 3

2c = –2

2c x 1/2 = 2 x 1/2

c = –1

A.

The student incorrectly applied the multiplication property of equality before the addition property of equality.

B.

The student did not apply the addition property of equality to isolate c.

C.

The student did not apply the multiplication property of equality to isolate c.

D.

The student correctly solved the two-step equation

Answers

Answer 1

Answer: For a. Isolate the y value. So -3y=8. Multiply both sides by -1/3, so y equals -8/3
For b. I would multiply the entire equation by 3 to get rid of the fraction. So the new equation is now -2t-6=-9. Isolate the variable, t, again. So it is now -2t=-3. Multiply both sides by -1/2, and t=3/2
For c. Nothing seems to be wrong except for the fact that you forgot a negative sign in one of the steps

Answer 2

Answer:

Answer:

t = 3

Step-by-step explanation:

Compute a value for t that satisfies the equation below.

t = 3

(pretty sure for B)

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If 3t-7=5t, then 6t=?

Answers

$3t-7=5t\n\n5t=3t-7\ \ \ \ /-3t\n\n5t-3t=3t-3t-7\n\n2t=-7\ \ \ \ /\cdot3\n\n2t\cdot3=-7\cdot3\n\n6t=-21$

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How to distribute this problem:
(x-8)^2 + 16

Answers

Answer:

We conclude that:

$\left(x-8\right)^2+16=x^2-16x+80$

Step-by-step explanation:

Given the equation

$\left(x-8\right)^2\:+\:16$

First, solve (x - 8)²

Apply Perfect Square formula: (a - b)² = a² - 2ab + b²

$a=x,\:\:b=8$

$\left(x-8\right)^2=x^2-2x\cdot \:\:8+8^2$

$=x^2-16x+64$

so the expression becomes

$\left(x-8\right)^2+16=x^2-16x+64+16$

$=x^2-16x+80$ Add the numbers: 64+16=80

Therefore, we conclude that:

$\left(x-8\right)^2+16=x^2-16x+80$

The graph of which function has a minimum located at (4, –3)?f(x) = x2 + 4x – 11
f(x) = –2x2 + 16x – 35
f(x) = x2 – 4x + 5
f(x) = 2x2 – 16x + 35

Answers

Answer:

None of the options is the answer to the question

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

$f(x)=a(x-h)^(2)+k$

where

(h,k) is the vertex of the parabola

case A) we have

$f(x)=x^(2)+4x-11$

In this case the x-coordinate of the vertex will be negative

therefore

case A is not the solution

case B) we have

$f(x)=-2x^(2)+16x-35$

This case is a vertical parabola open downward (the vertex is a maximum)

The vertex is the point $(4,-3)$ but is not a minimum

see the attached figure

therefore

case B is not the solution

case C) we have

$f(x)=x^(2)-4x+5$

Convert into vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-5=x^(2)-4x$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-5+4=(x^(2)-4x+4)$

$f(x)-1=(x^(2)-4x+4)$

Rewrite as perfect squares

$f(x)-1=(x-2)^(2)$

$f(x)=(x-2)^(2)+1$ --------> vertex form

The vertex is the point $(2,1)$

therefore

case C is not the solution

case D) we have

$f(x)=2x^(2)-16x+35$

Convert into vertex form

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$f(x)-35=2x^(2)-16x$

Factor the leading coefficient

$f(x)-35=2(x^(2)-8x)$

Complete the square. Remember to balance the equation by adding the same constants to each side

$f(x)-35+32=2(x^(2)-8x+16)$

$f(x)-3=2(x^(2)-8x+16)$

Rewrite as perfect squares

$f(x)-3=2(x-4)^(2)$

$f(x)=2(x-4)^(2)+3$ --------> vertex form

The vertex is the point $(4,3)$

therefore

case D is not the solution

The answer to the question will be the function

$f(x)=2x^(2)-16x+29$

I need help ASAP please. (Ill give 15 points if you help!)Alisha used the Given table to find the slope of a linear relationship . Find her Error and correct it :
Alisha's Answer:
The Slope ( m ) = 6