GCF of 24 , 36 , and 60

Answers

Answer 1

Answer:    24         36      60
1 × 24 1 × 36 1 × 60
2 × 12 2 × 18 2 × 30
3 × 8 3 × 12 3 × 20
4 × 6    4 × 9    4 × 15
      6 × 6 5 × 12
      6 × 10

GCF(24, 36, 60) = 12

Answer 2

Answer: To find the greatest common factor of any set:
1) List their prime factorizations.

24 = 2³ × 3
36 = 2² × 3²
60 = 2² × 3 × 5

2) Multiply together any factor these all share.

2² × 3 = 12 (GCF)

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Answers

The answer is $60. $30 × 12 = $360 – $300 = $60.

Valeriya filled a punch bowl with 0.25 dekaliters of orange juice, 375 centiliters ofcranberry juice, and 1.125 liters of sparkling water. How many more liters of juices
did Valeriya use than sparkling water?

Answers

Answer:

5.125 l

Step-by-step explanation:

Activity 4: Factor Then solve1. x^2+7x=0
2. 6s^2+18s=0
3. t^+8t+16=0
4. x^2-10x+25=0
5. h^2+6h=16
6. x^2-14=5x
7. 11r+15=-2r^2
8. x^2-25=0
9. 81-4x^2=0
10. 4s^2+9=12s

PLEAAASE HELP ME!

Answers

very complex, you should ask each individual question, or give more points
general strategy:
get 1 side to equal 0
factor
set each factor to 0
solve

1. factor out the x and set each to zero
x(x+7)=0
x=0

x+7=0
subtract 7
x=-7
x=0 or -7

2. factor out the 6s
6s(s+3)=0
6s=0
s=0

s+3=0
subtract 3
s=-3
s=-3 or 0

3. I'm assuming that the equation was supposed to be t^2+8t+16 so
find what 2 numbers multiply to get 16 and add to get 8
the numbers are 4 and 4
factor
(x+4)(x+4)=0
x+4=0
subtract 4
x=-4

4. find what 2 numbers multipy to get 25 and add to get -10
the numbers are -5 and -5
factor
(x-5)(x-5)=0
set each to zero
x-5=0
add 5
x=5

5. subtract 16 from both sides
h^2+6h-16=0
find what 2 numbers multiply to get -16 and add to get 6
the numbers are -6 and 10
factor
(h-6)(h+10)=0
set each to zero
h-6=0
add 6
h=6

h+10=0
subtract 10
h=-10
h=-10 or 6

6.subtract 5x from both sides
x^2-5x-14=0
find what 2 numbers multiply to get -14 and add to get -5
the numbers are -7 and 2
factor
(x-7)(x+2)=0
set each to zero
x-7=0
add 7
x=7

x+2=0
subtract 2
x=-2
x=-2 or 7

7.add 2r^2 to both sides
2r^2+11r+15=0
difficult so multiply 2 and 15 and get 30
not factor and find what 2 numbers multiply to get 30 and add to get 11
the numbers are 5 nd 6
split 11 up into 5 and 6
2r^2+6r+5r+15=0
group and factor
(2r^2+6r)+(5r+15)=0
factor
2r(r+3)+5(r+3)=0
reverse distribute
(2r+5)(r+3)=0
set each to zero
2r+5=0
subtract 5
2r=-5
divide 2
r=-5/2

r+3=0
subtract 3
r=-3
r=-3 or -5/2

8. this is a difference of 2 perfect squares in which if you have
x^2-y^2 that factors out of (x-y)(x+y) so
x^2-25=0
x^2-5^2=0
(x-5)(x+5)=0
set each to zero
x-5=0
add 5
x=5

x+5=0
subtract 5
x=-5
x=-5 or 5

9. differnce of 2 perfect squares
81-4x^2=0
9^2-(2x)^2=0
(9-2x)(9+2x)=0
set each to zero
9-2x=0
add 2x to both sides
9=2x
divde 2
9/2=x

9+2x=0
subtract 9 from both sidees
2x=-9
divide 2
x=-9/2
x=-9/2 or 9/2

10. subtract 12s from both sides
4s^2-12s+9=0
multiply 4 and 9 and get 36
find what 2 numbers multiply to get 36 and add to get -12
the numbers are -6 and -6
split up the -12s into -6s and -6s
4s^2-6s-6s+9=0
group
(4s^2-6s)+(-6s+9)=0
factor
2s(2s-3)+(-3)(2s-3)=0
reverse distribute
(2s-3)(2s-3)=0
set each to zero
2s-3=0
add 3
2s=3
divide 2
s=3/2

ANWERS:
1. x=0 or -7
2. s=-3 or 0
3. x=-4
4. x=5
5. h=-10 or 6
6. x=-2 or 7
7. r=-3 or -5/2
8. x=-5 or 5
9. x=-9/2 or 9/2
10. s=3/2

How many solutions does this system have?Y = x + 5
Y = -5x – 1
A) One
B) None
C) Infinite
D) Two

Answers

Well this does take some work on scratch paper but ill let you know that we have to plug these in to make one whole big equation
lets do that!
x + 5 = -5x - 1 now add +1 to both sides of the equation
+ 1 = +1 it cancels out on the right side and we solve on the left
*****************
x + 6 = -5x Now lets subtract that(1x) from both sides
-1x = -1x ( if x stands alone, theres always an imaginary 1 right by it)
************** now -5 - 1 = -6 so its -6x
6 = -6x Now divide both sides by -6 to isolate x to be alone
÷-6 = ÷6 It cancels out on the right side and we solve on the left
************ 6 ÷ -6 = 0 so lets see what we have
0 = x
Since zero is still a number this means there is only 1 solution!
Answer = A.) one
I hope this helps!
and dont forget 2
MARK ME BRIANLIEST!
=)

the product gives the coordinates of two points on line AB that has been rotated 90 degrees counterclockwise about the origin. name the coordinates of A’ and B’.

Answers

Since you haven't provided the coordinates of A and B, I cannot give an exact answer. However, I will help you with the concept.

Rotation 90° about the origin will result in the following:
(x,y) ..........> (-y,x)

Therefore, you have to multiply the y value by -1 and then flip the x and y.

Examples:
(2,9) ..........> Rotation 90° about the origin .........> (-9,2)
(-3,4) .........> Rotation 90° about the origin .........> (-4,-3)
(-1,0) ..........> Rotation 90° about the origin .........> (0,-1)
(8,-6) ..........> Rotation 90° about the origin .........> (6,8)

Hope this helps :)

A square has perimeter 12x. Find an expression, in terms of x, for the area of the square. Give your answer in its simplest form.

Answers

Answer:

Step-by-step explanation:

A square has 4 sides

$(12x)/(4)$ = 3x

Area is length times width, but we would square it in this case.

3x * 3x = $(3x)^(2)$ = 9 $x^(2)$

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Recall, is defined as the ratio of the circumference (say c) of a circle to its diameter (say d). That is, =c/d. This seems to contradict the fact that is irrational. How will you resolve this contradiction?