The situation described in the question pertains to wave propagation. Given that wave speed in a given medium is constant, and the relationship between wave speed, wavelength, and frequency, the wave in medium B, which has double the wavelength of the wave in medium A, would have half the frequency of the wave in medium A.
This question is about wave propagation between two different mediums, labeled 'A' and 'B'. The fundamental principle involved here is the dependence of wave speed on the medium through which it travels. However, it's necessary to recognize that wave speed also depends on wavelength and frequency. This relationship is encapsulated by the formula v = fλ, where v is wave speed, f is frequency, and λ is wavelength.
From the problem statement, we understand that the wavelength doubles when going from medium A to medium B. We are then asked to deduce the corresponding change in wave speed or frequency. If the wavelength doubles and the wave speed remains the same, the only possible adjustment is for the frequency to halve. So, the wave in medium B, compared to the wave in medium A, would have half the frequency (3). This is because wave speed in a given medium is constant and as per the formula, if wavelength increases, frequency must decrease.
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B) liquid phase
C) solid, liquid and gas phases
D) no phases are present at this point
Answer:
The answer is C) solid, liquid and gas phases
Explanation:
This point is called the triple point bc solid, liquid, and gas phases can exist together.
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The Objects separated by gravitational force of 360 N, masses 6.25 × 10¹⁴ kg and 7.20 × 10⁵ kg. Applying Newton's law with G = 6.67430 × 10⁻¹¹ m³ kg⁻¹ s⁻² yields distance is 2.79139 km.
We can apply Newton's law of universal gravitation to calculate the distance between the two objects. The formula takes the form:
F = (G ⋅ m₁ ⋅ m₂) / r²
Where:
F represents the force between the two objects
G stands for the gravitational constant (6.67430 × 10⁻¹¹ m³ kg⁻¹ s⁻²)
m₁ and m₂ denote the masses of the two objects
r indicates the distance between the centers of the two objects
Given that the force F = 360 N, m₁ = 6.25 × 10¹⁴ kg, and m₂ = 7.20 × 10⁵ kg, we can solve for r:
r² = (G ⋅ m₁ ⋅ m₂) / F
r = √((G ⋅ m₁ ⋅ m₂) / F)
Now, substituting the values and solving for r:
r = √(((6.67430 × 10⁻¹¹ m³ kg⁻¹ s⁻²) ⋅ (6.25 × 10¹⁴ kg) ⋅ (7.20 × 10⁵ kg)) / 360 N)
r ≈ 2791.39 m
Finally, converting the distance from meters to kilometers:
r ≈ 2.79139 km
Consequently, the two objects are approximately 2.79139 kilometers apart.
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