Answer:
5cm by 4cm by 10cm = 200
200 / 10 = 20
20 :>
Answer:
50.5°C
Explanation:
Start with the ideal gas law:
PV = nRT
Rearranging:
P/T = nR/V
Since the right side is constant (volume and mass don't change):
P₁ / T₁ = P₂ / T₂
This equation is also known as Gay-Lussac's law. Plugging in the values (make sure to use absolute pressure and temperature):
(32 psi + 14.7 psi) / (25 + 273.15) K = (36 psi + 14.7 psi) / T
Solving for T:
T = 323.69 K
T = 50.5°C
B) They are absorbed
C) The change into P-waves
D) They change into L-waves
Answer:
B) They are absorbed
Explanation:
B is correct because S waves can only travel through solid materials. When they hit liquid materials they are absorbed in and undetectable.
Answer:
B) They are absorbed
Explanation:
When they hit the liquid core, S-waves are no longer able to be detected. While P-waves bounce off the liquid core, S-waves are absorbed at the core.
Answer:
508Hz
Explanation:
A tuning fork with a frequency of 512 Hz is used to tune a violin. When played together, beats are heard with a frequency of 4 Hz. The string on the violin is tightened and when played again, the beats have a frequency of 2 Hz. The original frequency of the violin was ______.
When two sound waves of different frequency approach your ear, the alternating constructive and destructive interference causes the sound to be alternatively soft and loud - this phenomenon is beat production
frequency is the number of oscillation a wave makes in one seconds.
f1-f2=beats
therefore f1=512Hz
f2=?
beats=4Hz
512Hz-f2=4Hz
f2=512-4
f2=508Hz
the original frequency of the violin is 508Hz
The original frequency of the violin was 508 Hz. This is based on the principle of beats, where the beat frequency is the absolute difference in frequency between the two sources - in this case, the tuning fork and the violin string.
The original frequency of the violin string can be found using the principle of beats. The frequency of the beats is equal to the absolute difference in frequency between the two sources - in this case, the tuning fork and the violin string.
Initially, the beat frequency was heard as 4 Hz. This indicates that the original frequency of the violin was either 512 Hz + 4 Hz = 516 Hz, or 512 Hz - 4 Hz = 508 Hz. However, when the violin string was tightened, the beat frequency decreased to 2 Hz, which means the frequency of the note it was producing increased.
Therefore, the violin must have initially been producing a note with lower frequency (508 Hz), and even after tightening the string, the note it now produces (510 Hz) remains lower than that of the tuning fork.
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long and how
often have to do with exposure to chemicals?
Well how much, how long, and how often
For example how much is like how much a object is left in a small room with chemicals
How long is the time
how often is how much the same cycle is done repeatedly
D = distance between the cars at the start of time = 680 km
v₁ = speed of one car
v₂ = speed of other car = v₁ - 10
t = time taken to meet = 4 h
distance traveled by one car in time "t" + distance traveled by other car in time "t" = D
v₁ t + v₂ t = D
(v₁ + v₂) t = D
inserting the values
(v₁ + v₁ - 10) (4) = 680
v₁ = 90 km/h
rate of slower car is given as
v₂ = v₁ - 10
v₂ = 90 - 10 = 80 km/h
The slower car travels at 75 km/hr while the faster car travels at 85 km/hr. They meet up after both traveling for 4 hours, thereby covering the 680 kilometers between them.
The subject of this question is algebra - specifically involving rates of speed and time. Here's how you would find the answer:
The result would be 75 km/hr for the slower car and 85 km/hr for the faster car. They meet up after both traveling for 4 hours, thereby covering the 680 kilometers between them.
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