As the elements in Group 17 are considered in order of increasing atomic number, the chemical reactivity of each successive element decreases.
The impetus for a chemical substance to undergo a chemical reaction, either by itself or with other materials, with an ease and overall release of energy is referred to as reactivity.
Group 17 are the halogens group and on moving from top to bottom across that group atomic size of the atoms increases due to the increase in the number of energy shells. As a result of which it decreases the affect of nuclear attraction force to the outer most valence shell decreases.
Hence, reactivity decreases.
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B. -273
C. 273
Answer:
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Explanation:
Answer:hello
Explanation:
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Is correct! It should be answer(4) or (D)
Answer: 2.93 L
Explanation:
AI-generated answer
To find the volume occupied by 0.108 mol of helium gas at a pressure of 0.909 atm and a temperature of 306 K, we can use the ideal gas law equation:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.
Rearranging the equation to solve for V:
V = (nRT) / P
Plugging in the given values:
n = 0.108 mol
R = 0.0821 L·atm/(mol·K) (the ideal gas constant)
T = 306 K
P = 0.909 atm
V = (0.108 mol * 0.0821 L·atm/(mol·K) * 306 K) / 0.909 atm
Calculating this expression, we find that the volume occupied by 0.108 mol of helium gas at a pressure of 0.909 atm and a temperature of 306 K is approximately 2.93 L.
Now, let's consider the second part of the question: Would the volume be different if the gas was argon (under the same conditions)?
The volume would be the same for argon gas.
According to the ideal gas law, at the same temperature, pressure, and number of moles, the volume occupied by a gas is the same regardless of the gas's identity. Therefore, if we replaced helium gas with argon gas while keeping the same conditions of pressure, temperature, and number of moles, the volume occupied by argon gas would be the same, approximately 2.93 L.
1s2 2s2 2p3
1s2 2s2 2p4
1s2 2s2 2p6
1s², 2s², 2p⁴
Electronic configuration is the distribution of electrons of an atom in atomic orbitals. As we know Oxygen is a non metal and is present in group 6 and period 2 with atomic number 8. The atomic number in fact specifies the number of protons. Hence, for a neutral oxygen atom there must be 8 electrons to balance the charges of protons.
These 8 electrons are distributed in two main energy levels i.e. n = 1 and 2 and sub energy levels i.e. s and p. According to certain rules like Aufbau Principle, Pauli's Exclusion Principle and Hund's Rule the electronic configuration for eight electrons is as,
1s², 2s², 2px², 2p¹, 2p¹
The electronic configuration for oxygen is 1s2 2s2 2p4.
The electron configuration for oxygen is 1s2 2s2 2p4.
In the electron configuration, the numbers represent the energy levels (1s, 2s, 2p), and the superscripts represent the number of electrons in each orbital. The electron configuration follows the Aufbau principle, which states that electrons fill the lowest energy levels first.
In the case of oxygen, there are 8 electrons in total. The first two electrons fill the 1s orbital, the next two fill the 2s orbital, and the remaining four fill the 2p orbital (with two electrons each in the three 2p orbitals).
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Answer:
A) Biotechnology use can lead to a decrease in pesticide and herbicide use, maintaining soil quality.
Explanation:
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