When compared with the energy of an electron in the first shell of a carbon atom, the energy of an electron in the second shell of a carbon atom is .
Further explanation:
Quantum numbers:
Quantum numbers govern the size, energy, shape, and orientation of an orbital. The four quantum numbers are as follows:
1. Principal Quantum Number (n): It denotes the principle electron shell. The values of n are positive integers (1, 2, 3,…).
2. Angular Momentum Quantum Number (l): It represents the shape of an orbital. The value of l is an integer from 0 to (n-1).
3. Magnetic Quantum Number: This quantum number represents the orientation of the orbital in space. The value of lies between –l to +l. The formula to calculate the value of is as follows:
Therefore, the total number of values for a given value of l is 2l+1.
4. Electron Spin Quantum Number: It represents the direction of the electron spin. Its value can be or.
The formula to calculate the energy of an electron in an atom is as follows:
…… (1)
Here,
E is the energy of an electron.
Z is the atomic number of atom.
n is the principal quantum number.
Calculation of energy of an electron in the first shell of carbon atom.
The value of Z is 6.
The value of n is 1.
Substitute these values in equation (1) to calculate the energy of electron in the first shell.
Calculation of energy of an electron in the second shell of carbon atom.
The value of Z is 6.
The value of n is 2.
Substitute these values in equation (1) to calculate the energy of an electron in the second shell.
The negative sign in the energy of the electron in both the shells indicates that the electron is bound to the nucleus of an atom. So the energy of electron in the second shell of carbon atom is greater than its energy in the first shell of carbon atom and therefore option (2) is correct.
Learn more:
1. Which transition is associated with the greatest energy change? brainly.com/question/1594022
2. Describe the spectrum of elemental hydrogen gas: brainly.com/question/6255073
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Atomic structure
Keywords: energy of electron, n^2, Z^2, -13.6, n, Z, -122.4 eV, -489.6 eV, 6, 1, 2, first shell, second shell.
(2) 2 ppm (4) 0.02 ppm
The alpha decay of Radon-198 produces alpha particle and ¹⁹⁴₈₄Po.
Alpha decay is a type of radioactive disintegration in which some unstable atomic nuclei spontaneously expel an alpha particle to dissipate excess energy.
Alpha decay of Radon-198 is shown as:
¹⁹⁸₈₆Rn → ⁴₂He + ¹⁹⁴₈₄Po
In the above decay from the parent nuclei, daughter nuclei (¹⁹⁴₈₄Po) and alpha particle (⁴₂He) is produced.
Hence daughter nuclei of the alpha decay of Radon-198 is ¹⁹⁴₈₄Po.
To know more about alpha decay, visit the below link:
brainly.com/question/13512293
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Answer:
Need a control group.
Explanation: Without a control group you would not be able to interpret the results correctly.
B) Drug
C) Medicine
D) Screening Tool
Ohp xD nvm, the answer is A !
During the test trial, the sugar pill given to the control group is called a placebo. Therefore, the correct option is A. Placebo
A placebo is any drug or a treatment with no active substances, for example a sugar pill.
During clinical trials, usually one group takes the actual drug while the other group takes the placebo without being aware of it.
Placebo is an inactive treatment given to a group of people that is made to look like the real drug, but in reality it simply makes the patient believe they're being treated with the drug and that the drug will help them relieve from the symptoms.
By comparing the results from the two groups, this method helps in analyzing the accurate effects of the drug on the patients and helps in proving that it was the drug that actually treated the symptom and that the treatment did not occur by chance or just a mere belief of the patient thinking they will get better because they're being treated.
This approach helps reduce bias and ensures that the trial's results are more accurate and reliable.
So, the sugar pill given to the control group is called a placebo. Therefore, the correct option is A. Placebo
To learn more about placebo, click on
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