The population od a small country is 5,740,000. Express this number using scientific notation. Say steps to.

Answers

Answer 1

Answer: 5,740,000( you have to make the number less than 10

5.740000 ( you put a decimal to make it less )

5.74e6 (you count how many times you skipped over to get at the decimal point , and that's your awnser .

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Find def, help geometry

Answers

Answer:

Step-by-step explanation:

The algebra mat below models the equation x+3=5

Answers

x + 3= 5

The answer to this equation is simply 2

to do this:

subtract 3 from both sides of the equation.

3 cancels out, and you are left with this

x=2

so, the answer is x=2

or 2

Hope this helped!

Using the given zero, find one other zero of f(x). Explain the process you used to find your solution.2 - 3i is a zero of f(x) = x4 - 4x3 + 14x2 - 4x + 13.
*Can someone show the work I have the answers

Answers

The zeros of a function are the points where the function cross the x-axis.

One other zero of $\mathbf{f(x) = x^4 - 4x^3 + 14x^2 - 4x + 13}$ is 2 + 3i.

The zero of $\mathbf{f(x) = x^4 - 4x^3 + 14x^2 - 4x + 13}$ is given as:

$\mathbf{Zero = 2 - 3i}$

The above number is a complex number.

If a complex number a + bi is the zero of a function f(x), then the conjugate a - bi is also the zero of f(x).

This means that, one other zero of $\mathbf{f(x) = x^4 - 4x^3 + 14x^2 - 4x + 13}$ is 2 + 3i.

Read more about zeros of functions at:

brainly.com/question/22101211

Answer:

One other zero is 2+3i

Step-by-step explanation:

If 2-3i is a zero and all the coefficients of the polynomial function is real, then the conjugate of 2-3i is also a zero.

The conjugate of (a+b) is (a-b).

The conjugate of (a-b) is (a+b).

The conjugate of (2-3i) is (2+3i) so 2+3i is also a zero.

Ok so we have two zeros 2-3i and 2+3i.

This means that (x-(2-3i)) and (x-(2+3i)) are factors of the given polynomial.

I'm going to find the product of these factors (x-(2-3i)) and (x-(2+3i)).

(x-(2-3i))(x-(2+3i))

Foil!

First: x(x)=x^2

Outer: x*-(2+3i)=-x(2+3i)

Inner: -(2-3i)(x)=-x(2-3i)

Last: (2-3i)(2+3i)=4-9i^2 (You can just do first and last when multiplying conjugates)

---------------------------------Add together:

x^2 + -x(2+3i) + -x(2-3i) + (4-9i^2)

Simplifying:

x^2-2x-3ix-2x+3ix+4+9 (since i^2=-1)

x^2-4x+13 (since -3ix+3ix=0)

So x^2-4x+13 is a factor of the given polynomial.

I'm going to do long division to find another factor.

Hopefully we get a remainder of 0 because we are saying it is a factor of the given polynomial.

x^2+1

---------------------------------------

x^2-4x+13| x^4-4x^3+14x^2-4x+13

-( x^4-4x^3+ 13x^2)

------------------------------------------

x^2-4x+13

-(x^2-4x+13)

-----------------

So the other factor is x^2+1.

To find the zeros of x^2+1, you set x^2+1 to 0 and solve for x.

$x^2+1=0$

$x^2=-1$

$x=\pm √(-1)$

$x=\pm i$

So the zeros are i, -i , 2-3i , 2+3i

How to show the work and get the answer to 74.906+.01+42

Answers

You would write
74.906
+0.01
42
--------

Then you woulf add like that one column at a time and the awnser would be what the person above this said

Answer:

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Step-by-step explanation:

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Anyone tryana help me (:

Answers

is there a picture or other attachment with your question?

SImplify Each Expression~~~~~~~~~~~~~~~~~~
6x+(5x-8)

-(2-x)-3(6+8x)-12

11-(3x-6)+2(4x+5)-x

(x+2)-(x-2)-12x
~~~~~~~~~~~~~~~~~~~
-Please show work-

Answers

1) 6x+(5x-8)
Now combine like term
11x-8

2) (2-x)-3(6 + 8x)-12
distribute the negative sign and the -3
-2 + x - 18 - 24x - 12

then you have to combine like terms
-23x - 32

3) 11-(3x-6)+2(4x+5)-x

11-(3x-6)+8x+10x

11-3x+8x+10x
11-21x3

4) actually i don't know number 4 .

1) 6x+(5x-8)

Now combine like term

11x-8

2) (2-x)-3(6 + 8x)-12

distribute the negative sign and the -3

-2 + x - 18 - 24x - 12

then you have to combine like terms

-23x - 32

3) 11-(3x-6)+2(4x+5)-x

11-(3x-6)+8x+10x

11-3x+8x+10x

11-21x3