Answer:
option d
d ---- sin30 =5/x
Answer:
D. sin 30° = 5/x
Step-by-step explanation:
recall that for a right triange, considering one of the acute angles θ
sin θ = length of opposite side / length of hypotenuse
from the picture, we can see that
θ = 30°, length of opposite site = 5 and length of hypotenuse = x
substituting this into the above equation
sin 30° = 5/x
x - 7 < -4
-12/x> 10
x + 7 > 5
Substitute the value of x = -2 to the inequalities:
-3x < 1
(-3)(-2) < 1
6 < 1 FALSE
x - 7 < -4
-2 - 7 < -4
-9 < -4 TRUE
-12/x > 10
-12/(-2) > 10
6 > 10 FALSE
x + 7 > 5
-2 + 7 > 5
5 > 5 FALSE
Answer: x - 7 < -4
Answer: x - 7 < -4
Step-by-step explanation:
x - 7 < -4, plug in the -2.
-2 - 7< -4, simplify; -2+-7=-9
=- 9<-4
A.
2 • 2 • 2 • 3
B.
2 • 2 • 3 • 3
C.
2 • 2 • 9 • 1
D.
2 • 3 • 3 • 3
Answer:
75 kg
Step-by-step explanation:
%25 of ___ will give you 34.
____ x 0.20 = 34
____ = 34/0.20
34/0.20=170
___=170
Answer:
4.75x + 3.75y ≤ 15 inequality models the given situation.
Harper can buy at maximum 3 bags of fruits.
Step-by-step explanation:
Given : Harper has $15.00 to spend at the grocery store. She is going to buy bags of fruit that cost $4.75 each and one box of crackers that costs $3.50.
We have to write and solve an inequality that models this situation and could be used to determine the maximum number of bags of fruit that Harper can buy.
Let Harper buys 'x' bags of fruit
and 'y' box of crackers
Given : cost of one bags of fruits is $ 4.75
so the cost of x bags of fruits is 4.75x
Given : cost of one box of cracker is $ 3.50
so the cost of y box of crackers is 3.75y
also, Harper has $15.00 to spend at the grocery store
So the maximum amount he can spend is $15
So inequality become,
4.75x + 3.75y ≤ 15
So the maximum number of bags of fruit Harper can buy.
is when he buys no box of cracker.
Put y = 0 in above inequality , we have,
4.75x + 3.75(0) ≤ 15
4.75x ≤ 15
Divide both side by 4.75
We have , x = 3.158 ≈ 3
So , Harper can buy at maximum 3 bags of fruits.