Question:
Find the probability of getting a doublet in a throw of a pair of dice.
Answer:
The probability is 1 out of 6.
Explanation:
There are a total of 6 possibilities that you get a doublet, which is {1, 1}, {2, 2}, {3, 3}, {4, 4}, {5, 5}, and {6, 6}.
The total possibilities of throwing a dice are 6 possibilities for the first dice, and 6 possibilities for the second dice. Which results in a total of 6 × 6 = 36 possibilities available.
Probability = Possibilities of getting doublet ÷ Total possibilities = 6 ÷ 36 = 1 ÷ 6.
Hopefully this answer will help you.
(5x + 6)(3x - 2)
Answer: 15x2+8x-12
Step-by-step explanation: distribution property
(x, y) =
(smaller x-value)
(x, y)=
(larger x-value)
(x, y)=
Answer:
Let the original deposit be
x
Add $26 to original deposit
→
x
+
26
And doubled the sum
→
2
(
x
+
26
)
You get the new amount
→
2
(
x
+
26
)
=
264
Multiplying out the bracket
2
x
+
52
=
264
Subtract 52 from both sides
2
x
=
264
−
52
2
x
=
212
Divide throughout by 2
x
=
106
So the original amount was $106.00