Perform the indicated operations and express answers in simplest form.

3/x + 2/y - 4/xy

Answers

Answer 1

Answer: This will reqiure cross multiplication. We multiply by crossing the denominators and numerators. This is the solution : -

3/x + 2/y - 4/xy

= 3y+2x/xy - 4/xy                 (xy is common denominator)

=          3xy + 2x - 4
                  xy

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Solve for x: 6x – 8y = 12
What is the measure of RPQ
Find the equation of the perpendicular bisector of a line segment whose end points are (-3,9) and (-1,5)
In the equation x^2-6x+8=0 what are the solutions for x

Solve 2x^2+15x-8=0 and 2x^2+8x-24=0 for x

Answers

Answer:

X=.5

Step-by-step explanation:

put 2x^2+15x-8 into y1 of your calculator and 0 in y2 then second, trace, 5, enter, enter, enter. Then you have your answer

steps for patient medication decrease 25 mg per day for one week. Whats the change at end of the week?

Answers

The answer would be 25 mg minus the last day of the week

The change at the end of the week is 175

When dividing each of the numbers $$3759$$ and $$4139$$ by some positive integer number, the remainder happened to be equal to $$16$$. What is the smallest possible value of the divisor?

Answers

Answer:

The smallest possible value of the divisor is 19

Step-by-step explanation:

The given numbers for division are;

3759 and 4139, the remainder = 16

Let x represent the number

Therefore, we have;

x > 16

x is a factor of 3759 - 16 = 3743, and x is also a factor of 4139 - 16 = 4123

The factors of 3743 obtained from an online resource are 1, 19, 197, 3759

The factors of 4123 obtained from an online resource are 1, 7, 19, 31, 133, 217, 589, 4123

The common factors of 3743 and 4123 are 1, 19

Given that x > 16, we have, x = 19

Therefore, the smallest possible value that will divide both 3759 and 4139 whereby the remainder is 16 = 19

Half of j minus 5 is the sum of k and 13

Answers

$(1)/(2)j-5=k+13$

Final answer:

The statement 'Half of j minus 5 is the sum of k and 13' represents an algebraic equation and it can be written in the mathematical form as j/2 - 5 = k + 13. To solve for j, the equation can be rearranged to j = 2*(k + 13 + 5).

Explanation:

The question seems to involve solving an algebraic equation. First, let's convert the statement, 'Half of j minus 5 is the sum of k and 13', into its mathematical form.

Here 'half of j' can be written as j/2, 'minus 5' as '- 5', and 'the sum of k and 13' can be written as k + 13.

So the mathematical equation is: j/2 - 5 = k + 13.

If you need to solve this for j, you can rearrange the equation like so: j = 2*(k + 13 + 5). This formula will give you the variable j with respect to variable k.

Learn more about Algebraic Equation here:

brainly.com/question/32183344

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Prove that 1 - cosx / sinx = sinx / 1 + cosx
how?

Answers

Answer:

see explanation

Step-by-step explanation:

using the identity

cos²x = 1 - sin²x

consider the left side

$(1-cosx)/(sinx)$

multiply numerator/ denominator by (1 + cosx)

= $((1-cosx)(1+cosx))/(sinx(1+cosx))$ ← expand numerator

= $(1-cos^2x)/(sinx(1+cosx))$

= $(sin^2x)/(sinx(1+cosx))$ ← cancel sinx on numerator/ denominator

= $(sinx)/(1+cosx)$

= right side , thus proven

1.solve the following equation for y 3x- 2y= 62. solve the following equation 1/3(6x-9)= 3/4(4x-8)
3. solve 3(2x-1)/4= x + 7/2
the 3(2x-1) is over the 4 and the x + 7 is over the 2 i really dont understand them

Answers

So,

For number one, there will be an infinite number of solutions, as there are two placeholders.
3x - 2y = 6
It seems we can use the intercept method.
3x - 2(0) = 6
3x = 6

Divide both sides by 3
x = 2

This is one solution: (2,0)

3(0) - 2y = 6
-2y = 6

Divide both sidees by -2
y = -3

This is another solution: (0,-3)
You should now be able to draw the line.
If you want intercept form for this equation, just manipulate the equation in order to get the y = mx + b form.

Subtract 3x from both sides
-2y = -3x + 6

Divide both sides by -2
$y = (3)/(2) x + 6$

For the second problem, simply manipulate the equation.
$(1)/(3) (6x - 9) = (3)/(4) (4x - 8)$

Distribute
$2x - 3 = 3x - 6$

Subtract 2x from both sides
$-3 = x - 6$

Add 6 to both sides
$3 = x$

For the third problem, do the same thing.
$(3(2x-1))/(4) = x + (7)/(2)$

We must first multiply both sides by 4.
$3(2x-1) = 4x + 14$

Distribute
$6x - 3 = 4x + 14$

Subtract 4x from both sides
$2x - 3 = 14$

Add 3 to both sides
$2x = 17$

Divide both sides by 2
$x = (17)/(2) \ or\ 8 (1)/(2)$

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