MATHEMATICS HIGH SCHOOL

Find the equation of the perpendicular bisector of a line segment whose end points are (-3,9) and (-1,5)

Answers

Answer 1

Answer:

First find the equation of y.

$y=mx+n=(\Delta y)/(\Delta x)x+n$

Find the slope m.

$m=(5-9)/(-1-3)=(-4)/(-4)=1$ .

Pick one point, I'll pick (-3, 9). Insert coordinates in equation then compute n.

$9=1(-3)+n\implies n=12$ .

The equation of a line y is:

$y=x+12$ .

The perpendicular line $y_(\perp)$ is same like the normal line except its slope m becomes:

$k=-(1)/(m)=-1$ .

The equation of a perpendicular bisector is thus:

$y_(\perp)=-x+12$ .

Hope this helps.

Answer 2

Answer:

Answer:

$y = (1)/(2) x + 3$

Step-by-step explanation:

Using the given points, first find the slope:

m = (₂ - y₁) / (x₂ - x₁)

= (5 - 9) / (-1 - (-3))

= -4 / 2

= -2

Find y-intercept by using anyone of the give points and slope from above:

y = mx + b

5 = -2(-1) + b

5 = 2 + b

b = 3

With the m and b, you can make equation of line:

y = mx + b

y = -2x + 3

To find the perpendicular slope, make it opposite and inverse it.

m = -2 becomes 1/2

Regular equation of line:

y = -2x + 3

Perpendicular equation of line:

$y = (1)/(2) x + 3$

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Answers

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Letter D

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See more about functions at brainly.com/question/5245372

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Answers

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The table below shows the number of hours some college athletes in two states spend on indoor sports each week:State A 7 9 5 4 25 21 6 6 8
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Part A: Create a five-number summary and calculate the interquartile range for the two sets of data. (6 points)

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Answers

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Divide 7/15 by 3/5

A. 7/9
B. 75/21
C. 21/75
D. 7/25

Answers

7/15 ÷ 3/5 =
= 7/15 * 5/3 =
= 7/3 * 1/3 = (after simplifying)
= 7/9

Correct answer: A

Just keep in mind that dividing one fraction by another fraction is as much as multiplying the same fraction by an inverse of the second one.

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PLEASEEE HELP. Solve x^3-7x^2+6x-42=0

Answers

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x^2(x-7) + 6(x-7) = 0 [took x^2 out of the first two and a 6 out of the last two]
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$x^(3) -7 x^(2) +6x-42=0$

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Answers

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