#1
What is the distance between the points (4, 7) and (4, –5)?Distance between the points (4, 7) and (4, –5) is 12 units and distance between the points (–3, 5) and (2, –6) is 12.01 units.
The length along a line or line segment between two points on the line or line segment.
Distance=√(x₂-x₁)²+(y₂-y₁)²
The distance between the points (4, 7) and (4, –5)
x₁=4, y₁=7, x₂=4, y₂=-5
Distance=√(x₂-x₁)²+(y₂-y₁)²
Distance=√(4-4)²+(-5-7)²
=√(-12)²
=√144
=12
Hence distance between the points (4, 7) and (4, –5) is 12 units.
the distance between the points (–3, 5) and (2, –6)
x₁=-3, y₁=5, x₂=2, y₂=-6
Distance=√(x₂-x₁)²+(y₂-y₁)²
=√(2-(-3))²+(-6-5)²
=√(5)²+(-11)²
=√25+121
=√146
=12.08
So distance between the points (–3, 5) and (2, –6) is 12.01 units.
Hence distance between the points (4, 7) and (4, –5) is 12 units and distance between the points (–3, 5) and (2, –6) is 12.01 units.
To learn more on Distance click:
#SPJ2
Answer:
7 mph
Step-by-step explanation:
Let x be the speed in still water hence
Time to move downstream will be
Time to move upstream will be
Difference will be
x=7
Answer:
The answer is 24 liters
Step-by-step explanation:
I got it right during math class