Explain how you can identify fractions that are equal to one

Answers

Answer 1

Answer: If the numerator and denominator is the same then it will equal 1. For ex: $(2)/(2)$ equal 1

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PLEASE help with these math questions

Answers

Hi there,

No. 1:

$64<68<81\Rightarrow √(64)<√(68)<√(81),\;or\;√(8^2)<√(68)<√(9^2)\Rightarrow\n\n\Rightarrow therefore\;8<√(68)<9.$

The answer is 8.2 ft, for sure.

Having this technique in mind, can you resolve the rest of 4 math questions, by yourself ? It is quite simple, isn't it ?

Green eyes.

to estimate
find the perfect squares above and below the target number
guess
example
sqrt of 99
9^2=81
10^2=100
99 is between 81 and 100, closer to 100 so therefor pick 10.9 or something

1.
if we estimate
8^2=64
that is close to 68
8.2^2 is probably closer sinnce is is bigger than 0.2

therefor the answer is A

2. estimate
12^2=144
13^2=169
148 is betwen 12 and 13
pick B

3. 114
square aera=side^2
10^2=100
11^2=121
see if it is more than 10.5 or less
which is closer 114
100 or 121
121 is closer
therefor we guess that it is greater and therefor we should guess 11 yards

4. area=side^2
196=side^2
luckily we remembered tat 14^2=196
1 side=14 ft
perimiter=4side
P=4*14=56 ft

5.
area=side^2
480=side^2
sqrt both sides
√480=√16√30=4√30
aprox sqrt 30
between 5 and 6, lookks like in middle
aprox 5.5
4*5.5
perimiter is times 4
4*4*5.5=16*5.5=80+8=88 feet
answer is D

Simplify (8j^3 - 3j^2 + 5)-(4j^3+8j^2+7j-6)

Answers

Answer:

4j^3 + 5j^2 + 7j - 1

Step-by-step explanation:

(8j^3 - 3j^2 + 5)-(4j^3+8j^2+7j-6)

Distribute the -1 in front of the (4j^3+8j^2+7j-6)

8j^3 - 3j^2 + 5 - 4j^3 + 8j^2 + 7j - 6

We can combine anything with the same exponent number that "j" is raised to

8j^3 - 4j^3 = 4j^3

-3j^2 + 8j^2 = 5j^2

7j is just 7j since there is nothing else with just j in it

5 - 6 = -1

Add these together

4j^3 + 5j^2 + 7j - 1 is our final answer

Which one is it please help

Answers

The answer to m1= 130

What is 200 +78÷4×2 10% =

Answers

First, evaluate 200+78÷ 4x2. Which equals 239. Now, 10% of 239 = 23.9

In year 13, the scientist will put tree wrap around tree 1 to protect it from the winter snow. The height of the tree wrap needs to be 45 inches.The wrap is priced by the square foot. To the nearest square foot, how many square feet of wrap does she need?

Answers

Answer: 3 feet 9 inches

Step-by-step explanation: Hopes this helps

Final answer:

To find the square footage of the tree wrap needed, calculate the area by multiplying the height and width of the wrap. Then, convert the square inches to square feet by dividing by 144.

Explanation:

To find the square footage of the tree wrap needed, we need to calculate the area of the wrap that will be wrapped around the tree. The height of the tree wrap is given as 45 inches. To find the width of the tree wrap, we need to measure the circumference of the tree. Let's say the circumference of tree 1 is 120 inches. To calculate the width, we divide the circumference by 3.14 (pi). So, the width is approximately 38.22 inches (rounded to two decimal places).

To calculate the area of the wrap, we multiply the height by the width. In this case, the area is approximately 1719.9 square inches (rounded to one decimal place). To convert this to square feet, we divide by 144 (since there are 144 square inches in a square foot). So, the approximate square footage of wrap needed is 11.94 square feet.