The figure shows two right trapezoids. Trapezoid A B C D has right angles at B and C. Angle B is adjacent to the shorter parallel side. Angle C is adjacent to the longer parallel side. Angle A is obtuse. Angle D is acute. Sides A B and C D are parallel. The sides in order of length from shortest to longest are B C, A D, A B, and C D. Trapezoid R S P Q has right angles at S and P. Angle S is adjacent to the shorter parallel side. Angle P is adjacent to the longer parallel side. Angle R is obtuse. Angle Q is acute. Sides R S and P Q are parallel. The sides in order of length from shortest to longest are S R, R Q, R S, and P Q.The two figures shown above are congruent. Identify the corresponding sides and angles.
please help this is all they gave me
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Answer:
In the trapezoids ABCD and RSPQ,
Angles A, B, C and D are corresponding to the angles R, S, P and Q respectively,
Also, the sides AB, BC, CD and DA are corresponding to the sides RS, SP, PQ and QR respectively.
Since, when two figures are congruent to each other then their corresponding sides and angles are also congruent.
Here, trapezoids ABCD and RSPQ are congruent.
Therefore, AB≅RS, AB≅RS, AB≅RS, AB≅RS
And, ∠A ≅ ∠R, ∠B ≅∠S, ∠C≅∠P, ∠D≅∠Q
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I dont know the answer. Can someone help me ?
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It is B I hope it helps
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Jeremy has three 50 pence coins.
Final answer:
To answer the problem, the coins of Janice must be a penny, dime, and a nickel which total up to $0.16, while Jeremy's coins are three dimes and two pennies totaling $0.32
Explanation:
The problem can be approached by considering the different coins you have available and their values. In the U.S, these are penny ($0.01), nickel ($0.05), dime ($0.10), quarter ($0.25), half dollar ($0.50), and dollar ($1.00). Because Jeremy's coins are all the same and twice Jane's total, this limits us to lower value coins.
Let's start with Jane. She can't have a quarter because Jeremy doesn’t have $0.50 coins. If she had a dime, Jeremy would need two dimes but we know all his coins are the same so this isn't possible. This means Jane must have a penny ($0.01), a nickel ($0.05) and a dime ($0.10) for a total of $0.16. Therefore, Jeremy, whose total is twice Jane's, must have $0.32 which can be achieved by having three dimes ($0.10 x 3 = $0.30) and two pennies ($0.01 x 2 = $0.02).
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1) Simplify
4x−20−8=−28+6x
2) Simplify 4x−20−8 to 4x−28
4x−28=−28+6x
3) Group all terms
4x−28=6x−28
4) Cancel −28 from eachside
4x=6x
5) Move all of the terms to one side
4x−6x=0
6) Simplify equation 4x−6x to −2x
−2x=0
7) Divide each side by −2
x=0
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f(x)*g(x) = (4x²+6)/2 * 3/(2x²+3) = 2(2x²+3)/2 * 3/(2x²+3) = (2x²+3) * 3/(2x²+3) =3
Answer is D.3