MATHEMATICS MIDDLE SCHOOL

~Please only answer if you know for sure~You bought a car for $20,000. You have owned it for one year, and it is now worth $16,000. What is the percent decrease in your car's value?

20%


25%


80%


125%

Answers

Answer 1
Answer:

Answer:

Option A. 20%

Step-by-step explanation:

Since the cost price of the car when it was new = $20000

After one year car value $16000.

We have to calculate the depreciation in the price or my car.

So decease in the car's value = 20000-16000 = $4000

Since cost price of the car was = $20000

therefore % decrease decrease in the price will be = (decrease in price/cost price)×100 = (4000/20000)×100 = 20%
Answer 2
Answer: 20%.

20,000 times 0.8 is 16,000, so the decreased value that was lost was 20% of the original price.

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35/4 square meters by 7/2 meters

Answers

Area = 35/4  m²

Length = 7/2 m

Area =  length * width

35/4 =  7/2 * width

7/2 * width = 35/4

width = 35/4 ÷ 7/2

width = 35/4  × 2/7 = 5/2

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Find three numbers that each have a multiple of 30.

Answers

I'm guessing you mean "What are three multiples of 30?" so 60, 90, 120 OR 5 x 6 = 30, 3 x 10 = 30, 15 x 2 = 30.

Which is a graph for the inequality m<(or equal to)-2?

Answers

Answer:

cool

Step-by-step explanation:

a store owner is arranging clothing on racks. She has 30 sweaters, 45 shirts and 15 pairs of jeans. She wants to put the same number of items on each rack, with only one type of item on each. How many items can she put on a rack?

Answers

I think what the teacher wants is 15  which is the greatest common factor of all three numbers and the factors of 15 are 
1 x 15 and 3 x 5 so the she can put one of each, or she can put 3 of each,
 or she can put 5 of each , or she can put 15 of each.

The problem is unclear however because as worded she could put 2 sweaters, 2 shirts and 2 pair of jeans.  I think the teacher wants all the jeans used.  The number 1,3,5 and 15 will use up all of the jeans.
1 jean on 15 racks
or 3 jeans on 5 racks
or 5 jeans on 3 racks
or 15 jeans on one rack

These are the sort of ambiguous word problems 4th graders are exposed to on a daily basis.  As the gentleman mentioned, the teacher expects 15, the largest common factor but 1 on each rack fits as well. It should have read “what’s the maximum number of the same item can he/she place on the racks?”

What is the volume of a cube with a side length of 5 cm? help asapA) 10 cm


B) 15 cm


C) 25 cm


D) 125 cm

Answers

V = a * b * c 
a,b,c- lengths of sides 
in here a=b=c=5cm 
V=5*5*5 = 125 cm^3

or 
V=a^3 = 5^3 =125 cm^3

Adult tickets to a basketball game cost $5 and student tickets are $1. A total of $2,874 was collected when selling 1,246 tickets. How many of each type of ticket were sole

Answers

x-\ adult\ tickets\n\ny-\ student\ tickets\n\n \left \{ {{x+y=1246} \atop {5x+1y=2874\ \ | *(-1)}} \right. \n\n \left \{ {{x+y=1246} \atop {-5x-1y=-2874}} \right. \n+--------\n\naddition\ method\n\n-4x=-1628\ \ \ | divide\ by\ -4\n\n x=407\n\n y=1246-x\n\ny=1246-407=839\n\n There\ were\ 407\ adult\ tickets\ and\ 839\ student\ tickets.
5x+1y=2874
x+y=1246
Im going to use subtraction
5x+y=2874
-x-y=-1246

4x=1628
x=407 adults
407+y=1246
y=839 students
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